The last time we ran a gel, we ran a 1% gel. Why would we choose to run a 3% gel today on the worms
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The last time we ran a gel, we ran a 1% gel. Why would we choose to run a 3% gel today on the worms?
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- You inoculated a culture with an initial cell count of 6.5x10^3 cells. The generation time for this organism is 25 minutes. You grew the culture for 10 hours. a) How many generations occurred?b) How many cells will be present after the 10 hours?The last time we ran a gel, we used a 1kB molecular weight marker. Why would we choose to use a 100bp marker today on worms?A culture with approximately 4x105 cells/mL were incubated. After 10 hours, the number of cells had increased to 5x109. a) How long was the generation time in minutes?b) How many generations have occurred?
- Steven is a lab research assistant. He mixed 25 µL of cells with 50 µL of cell culture media in tube-A, then transferred 10 µL to the hemocytometer and started counting cells, then realized the cells were too crowded to count accurately, so Steven took an aliquot of 20 µL cells of cells from tube-A and mixed with 180 µL of cell culture media, transferred 10 µL onto the hemocytometer, and countered 500 cells from the squares on the four corners of the hemacytometer. What is the # of cells per mL? Please show all calculation steps.In a serial dilution, you plate 1 ml of a 1/1000 dilution of a bacterial culture and find 25 colonies the next day. What was the concentration of cells in the original culture? A) 25 cells/ml B) 0.000025 cells/ml C) 25,000 cells/ml D) 26 cells/ml E) 0.025 cells/mlWhich of the following is true of the gel electrophoresis shown? Note: Only one can be true... I'm between c or d. Previous answer confused me more. A) the power source has not been turned on yet. B) the three wells contained the same DNA molecules. C) well #1 had fewer molecules of DNA than well #2 or #3 D) well #3 had more different sized molecules of DNA than well #1 or #2
- A scientist transfers 0.1 mL phage stock to a tube containing 9.9 mL tryptic soy broth. She then transfers 0.1 mL from that tube to a second tube containing 9.9 mL. She then plated 0.1 mL of the content in the second tube. The total fold of dilution is: a) 100,000x b) 1000x c) 100x d) 10,000xIn Figure 5-5,a. Why do A− and B− cells, by themselves, not formcolonies on the plating medium?b. What genetic event do the purple colonies in themiddle plate represent?You take 10 ml of a stock solution, which is at a concentration of 1000 phage/ml, and dilute it to a total of 100 ml. From the resulting solution you take 5 ml and dilute it to 25 ml, and from the latter you take 5 ml and make a total of 20 ml. a) It will be possible to know how many bacteriophage particles there will be in 1 ml of the last solution b) What is the dilution factor in each step, in the same order in which the dilutions are made? c) What is the total serial dilution factor?
- You want to subculture your cells from T25 flask to 96-well plates. You first collected your cells in a tube with 5ml of culture medium. Then carried out a trypan blue assay and counted your cells with a hematocytometer as shown in Figure below. Answer the questions according to the results: a. Calculate the concentration of the stock including the dead and living cells. Dont forget to show the units! b. Calculate the percentage (%) of the living cells in the stock. c. You want to seed 6000 living cells into each well of 96 well plates, then calculate the volume you should take from the stock for each well. 輯 1 mm I IREIn the experiment by Bernard Davis, bacterial F+cells and F- cells were growing while separated by a filter. Filter pores allowed the passage of the liquid medium but not the bacteria cells. As a result: 1) prototype colonies grew well on minimal medium 2) F+ cells were converted to F- cells despite the physical separation 3)F- cells were converted F+ cells despite the physical separation 4)F+ cells were not converted to F- cells because of the physical separation 5) F- cells were not converted to F+ cells because of the physical separation 6)there was no growth of prototypes on minimal mediumYou have 1 ml of kombucha. You remove 0.1 ml of this and mix it with 9.9 ml of fresh tea. You mix the second tube, then remove 1 ml of this mixture and add it to 9 ml of fresh tea. You then mix this, and remove 0.1 ml of this solution, and plate it. The next day, you return to find 362 colonies. What was the concentration of the cells in the original mix? Show your calculations. My professor worked this problem out in class but she used a different method than that from the Khan academy videos on youtube and I am getting lost in the steps. Do you mind labeling?