the non-homogeneous equation y” – 2y’ = t + dt, then determine this solution
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the non-homogeneous equation y” – 2y’ = t + dt, then determine this solution
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- FY Find the two components of the force (200 N) if a= 60 degrees, as :shown in the figure below F= 200 N α= 60 FX (FX= 100 N) AND (FY= 73.2N) O (FX= 173.2 N) AND (FY= 100N) O (FX= 100 N) AND (FY= 173.2N) OQ3: 2- Find the value of F, if P=360N, a=15°, B=25°, and the resultant is acting along the X-аxis. Y F 475.7N 587.8N 695.5N 797.8NThe following term remain constant when external force on the system is zero is
- The resultant forces in two * :directions are P=300N K=200N 30 Ry =RX=Zero O RX=312.12N and RY= 38.92N O RX= 38.92N and RY= 312.12N3m Find the rectangular representation of the force F, given that its magnitude 240 N. * F = -135.76 i+ 169.71 j– 101.82 k F = 135.76 i + 169.71 j+ 101.82 k F = 135.76 i - 169.71 j+ 101.82 k F = -135.76i+ 169.71 j+ 101.82 k3. Find the resultant force and its direction. Use the Ccmponent method. 100 N 110N 30 3ON 160N
- [Q1] Find the resultant for the force system shown below: 700 N 450 N 300 Ν |30 60° В 1500 N-m to - 3 m - -2 m - -4 mFind the component of the force F = -7i + 8j – 9k lb along the line through the origin makingequal acute angles with the coordinate axes.How would the last part of this problem be solved (finding the magnitude of the resultant vector in terms of the two constants given the normalizing term n)?