The observer is in air nearly above the object submerged in water (index of refraction 1.33). The depth of the object is 8.4cm. Find the apparent depth of the object. (Hint: Use Snell's law of refraction and the fact that the angles of incidence and refraction are small, so tan 0 sin 0.) Number i Units Observer Apparent depth=d Actual depth = d

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The observer is in air nearly above the object submerged in water (index of refraction 1.33). The depth of the object is 8.4cm. Find the
apparent depth of the object. (Hint: Use Snell's law of refraction and the fact that the angles of incidence and refraction are small, so tan 0
sin 0.)
Number i
Units
Observer
Apparent
depth=d Actual
depth = d
Transcribed Image Text:The observer is in air nearly above the object submerged in water (index of refraction 1.33). The depth of the object is 8.4cm. Find the apparent depth of the object. (Hint: Use Snell's law of refraction and the fact that the angles of incidence and refraction are small, so tan 0 sin 0.) Number i Units Observer Apparent depth=d Actual depth = d
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