The period of the pendulum T (in s) is given below, where L-length of pendulum (in m), g-9.8 m/s². - 2 √ T= 2TA 1. Draw a free body diagrams of a pendulum while in motion. Rf = restoring force T= tension w = weight T 0. 2000 吧 W Data and Calculations Table 1 Mass (kg) 0.0500 0.1000 T₁(s) 1.9175 S 1.9293 1.9261s T₂(s) 1.91445 1.9911 s 1.9376 s 7 Error Length L= 87 cm = 0.87 m T3(s) Taverage(s) 1.9139 1.9153 s 1.92785 1.94945 1.9305 1.9314. 1.9153-2 x 100 2 = -4.24 S -4.24 -2.53 -3.43 @1.9494-2x100 2 = -2.53 S 2. Calculate the period T for the length that was used Tstandard- punto à from the stope %error=ITaverage -Tstandard I/Tstandard x 100=_ % Error 5. Does the period depend on the mass of the pendulum? Explain.

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Hello, can you please help me do part 2
The period of the pendulum T (in s) is given below, where L-length of pendulum
(in m), g=9.8 m/s².
T = 271
1. Draw a free body diagrams of a pendulum while in motion.
restoring force
L
9
0.1000
Rr t
Data and Calculations Table 1
Mass (kg)
0.0500
0. 2000
W
T₁(s)
T₂(s)
1.9175 S
1.91445
1.9293 1.9911 s
1.9261 s 1.9376 s
Error
T3(S)
Taverage(s)
1.9139 1.9153 s
1.92785 1.9494 s
1.9305 1.9314 s
1.9153-2 x 100
2
= -4.24
2. Calculate the period T for the length that was used Tstandard=__
Rf=
T= tension
W =
weight
Length L= 87 cm = 0.87 m
%error=ITaverage -Tstandard I/Tstandard x 100=_
% Error
- 4.24
-2.53
-3.43
21.9494-2 x 100
2
= -2.53
The
5. Does the period depend on the mass of the pendulum? Explain.
is a function of l&g only.
period
Here there is no dependence of mass with
the penod
31.9314-2
2
= -3.43
x 100
Transcribed Image Text:The period of the pendulum T (in s) is given below, where L-length of pendulum (in m), g=9.8 m/s². T = 271 1. Draw a free body diagrams of a pendulum while in motion. restoring force L 9 0.1000 Rr t Data and Calculations Table 1 Mass (kg) 0.0500 0. 2000 W T₁(s) T₂(s) 1.9175 S 1.91445 1.9293 1.9911 s 1.9261 s 1.9376 s Error T3(S) Taverage(s) 1.9139 1.9153 s 1.92785 1.9494 s 1.9305 1.9314 s 1.9153-2 x 100 2 = -4.24 2. Calculate the period T for the length that was used Tstandard=__ Rf= T= tension W = weight Length L= 87 cm = 0.87 m %error=ITaverage -Tstandard I/Tstandard x 100=_ % Error - 4.24 -2.53 -3.43 21.9494-2 x 100 2 = -2.53 The 5. Does the period depend on the mass of the pendulum? Explain. is a function of l&g only. period Here there is no dependence of mass with the penod 31.9314-2 2 = -3.43 x 100
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