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The pressure in an ideal gas is given by PV = RT, where T is the temperature of the gas, V is the volume and Ris a constant. Determine the maximum possible percentage error in P when T and V are measured to within an accuracy of 6% and 5% respectively. My attempt so far: From the ideal gas law: P = P(T,V) RT The differential dP is given by V dP dP dT + dT R RT IP dV , V² dP dV APAP so dP R RT R RT dT IP- V²P AP V(RT/V) LP- V²(RT/V) AP- т AP V P VP and dP dT dV dT dV + V 6% + 5% = 11% . %3D %3D P T V After this I draw a blank. Could someone please fill in the blank and show me what I ned to do next? Thanks.

The pressure in an ideal gas is given by PV = RT, where T is the temperature of the gas, V is the volume and Ris a constant. Determine the maximum possible percentage error in P when T and V are measured to within an accuracy of 6% and 5% respectively. My attempt so far: From the ideal gas law: P = P(T,V) RT The differential dP is given by V dP dP dT + dT R RT IP dV , V² dP dV APAP so dP R RT R RT dT IP- V²P AP V(RT/V) LP- V²(RT/V) AP- т AP V P VP and dP dT dV dT dV + V 6% + 5% = 11% . %3D %3D P T V After this I draw a blank. Could someone please fill in the blank and show me what I ned to do next? Thanks.

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The pressure in an ideal gas is given by PV = RT, where T is the temperature of the gas, V is the volume and Ris a constant. Determine the maximum possible percentage error in P when T and V are measured to within an accuracy of 6% and 5% respectively. My attempt so far: From the ideal gas law: P = P(T, V) : RT The differential dP is given by V dP dP R IP APAP dT dV RT dV V2 dP sO dP RT R dT VP RT R dT dV V²P AP- V(RT/V) AP V²(RT/V) T P IP- V and dP dT dV dT| dV 6% + 5% = 11% . T V T V After this I draw a blank. Could someone please fill in the blank and show me what I need to do next? Thanks.
Transcribed Image Text:The pressure in an ideal gas is given by PV = RT, where T is the temperature of the gas, V is the volume and Ris a constant. Determine the maximum possible percentage error in P when T and V are measured to within an accuracy of 6% and 5% respectively. My attempt so far: From the ideal gas law: P = P(T, V) : RT The differential dP is given by V dP dP R IP APAP dT dV RT dV V2 dP sO dP RT R dT VP RT R dT dV V²P AP- V(RT/V) AP V²(RT/V) T P IP- V and dP dT dV dT| dV 6% + 5% = 11% . T V T V After this I draw a blank. Could someone please fill in the blank and show me what I need to do next? Thanks.
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