The rate of change of atmospheric pressure P with respect to altitude h is proportional to P, provided that the temperature is constant. At a specific temperature the pressure is 102.3 kPa at sea level and 88 kPa at h = 1,000 m. (Round your answers to one decimal place.) (a) What is the pressure (in kPa) at an altitude of 3,500 m? kPa (b) What is the pressure (in kPa) at the top of a mountain that is 6,365 m high? kPa

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter1: Units And Measurement
Section: Chapter Questions
Problem 43P: A commonly used turn of mass in the English system Is the pound-mass, abbreviated Ibm, where 1 Ibm =...
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The rate of change of atmospheric pressure P with respect to altitude h is proportional to P, provided that the temperature is constant. At a specific temperature the pressure is 102.3 kPa at sea level and 88 kPa
at h = 1,000 m. (Round your answers to one decimal place.)
(a) What is the pressure (in kPa) at an altitude of 3,500 m?
kPa
(b) What is the pressure (in kPa) at the top of a mountain that is 6,365 m high?
kPa
Transcribed Image Text:The rate of change of atmospheric pressure P with respect to altitude h is proportional to P, provided that the temperature is constant. At a specific temperature the pressure is 102.3 kPa at sea level and 88 kPa at h = 1,000 m. (Round your answers to one decimal place.) (a) What is the pressure (in kPa) at an altitude of 3,500 m? kPa (b) What is the pressure (in kPa) at the top of a mountain that is 6,365 m high? kPa
A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium divides into two cells every 20 minutes. The initial population of a culture is 74 cells.
(a) Find the relative growth rate. (Assume t is measured in hours.)
k =
(b) Find an expression for the number of cells after t hours.
P(t) =
(c) Find the number of cells after 8 hours.
cells
(d) Find the rate of growth after 8 hours. (Round your answer to three decimal places.)
billion cells per hour
(e) When (in hours) will the population reach 20,000 cells? (Round your answer to two decimal places.)
h
Transcribed Image Text:A common inhabitant of human intestines is the bacterium Escherichia coli. A cell of this bacterium in a nutrient-broth medium divides into two cells every 20 minutes. The initial population of a culture is 74 cells. (a) Find the relative growth rate. (Assume t is measured in hours.) k = (b) Find an expression for the number of cells after t hours. P(t) = (c) Find the number of cells after 8 hours. cells (d) Find the rate of growth after 8 hours. (Round your answer to three decimal places.) billion cells per hour (e) When (in hours) will the population reach 20,000 cells? (Round your answer to two decimal places.) h
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