The reaction below is second order in [H202] and has a rate constant of 0.071 M-1m- 1: 2H2O2 (1) → 2H20 (1) + O2 (g) What is the solution concentration after 58 minutes if it was originally 0.14 M H202?
The reaction below is second order in [H202] and has a rate constant of 0.071 M-1m- 1: 2H2O2 (1) → 2H20 (1) + O2 (g) What is the solution concentration after 58 minutes if it was originally 0.14 M H202?
Chemistry by OpenStax (2015-05-04)
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ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
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Chapter12: Kinetics
Section: Chapter Questions
Problem 41E: The reaction of compound A to give compounds C and D was found to be second-order in A . The rate...
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What is the solution concentration after 58 minutes if it was originally 0.14 M H2O2? Round your answer to the nearest 10th of a minute.
![The reaction below is second order in [H202] and has a rate constant of 0.071 M-1m-
1:
2H2O2 (1) → 2H20 (1) + O2 (g)
What is the solution concentration after 58 minutes if it was originally 0.14 M H202?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd37d50d8-93d1-467d-90d5-13298d0e52a9%2Ff6496356-324b-4921-b77b-d2ee81abca43%2Fjwqlu1f_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The reaction below is second order in [H202] and has a rate constant of 0.071 M-1m-
1:
2H2O2 (1) → 2H20 (1) + O2 (g)
What is the solution concentration after 58 minutes if it was originally 0.14 M H202?
Expert Solution
Step 1
Kinetics based on second order rxn....
1/[A] = kt + 1/[A]0
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