The shot put world record for women stands at 22.63 m (Natalya Lisovskaya, 1987). Assuming that the shot is projected from a height of 2.2 m at an angle of 45° and neglecting air resistance, the initial speed of the particle is 14.22 m/s. Use g = 9.81 ms-2 for the gravitational acceleration on the surface of the Earth. Parameters (x(+)), z(+)): Vo x(+) 늘 = 2(+) = 글 gta Vo t + √√2 + Zo 1. Find the maximal height of the shot, using the parameters. Give a general expression (no numbers substituted in yet), then evaluate this expression to 2 digits accuracy. 2. Eliminate time t to find an implicit expression of the form z(x) of the solution curve. Use this expression to again determine the maximal height of the shot. 3. Use conservation of energy to determine the maximal height of the shot. You should find the same answer with all three methods.

Glencoe Physics: Principles and Problems, Student Edition
1st Edition
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Paul W. Zitzewitz
Chapter6: Motion In Two Dimensions
Section6.3: Relative Velocity
Problem 27PP
icon
Related questions
Question
The shot put world record for women stands at 22.63 m (Natalya Lisovskaya, 1987). Assuming that
the shot is projected from a height of 2.2 m at an angle of 45° and neglecting air resistance, the initial
speed of the particle is 14.22 m/s. Use g = 9.81 ms-2 for the gravitational acceleration on the surface
of the Earth.
Parameters
(x(+)), z(+)):
x(t) =
2(+) =
9 +2
+
شاد
t
+ Zo
1. Find the maximal height of the shot, using the parameters. Give a general expression (no
numbers substituted in yet), then evaluate this
expression to 2 digits accuracy.
2.
3.
Eliminate time t to find an implicit expression of the form z(x) of the solution curve. Use this
expression to again determine the maximal height of the shot.
Use conservation of energy to determine the maximal height of the shot.
You should find the same answer with all three methods.
Transcribed Image Text:The shot put world record for women stands at 22.63 m (Natalya Lisovskaya, 1987). Assuming that the shot is projected from a height of 2.2 m at an angle of 45° and neglecting air resistance, the initial speed of the particle is 14.22 m/s. Use g = 9.81 ms-2 for the gravitational acceleration on the surface of the Earth. Parameters (x(+)), z(+)): x(t) = 2(+) = 9 +2 + شاد t + Zo 1. Find the maximal height of the shot, using the parameters. Give a general expression (no numbers substituted in yet), then evaluate this expression to 2 digits accuracy. 2. 3. Eliminate time t to find an implicit expression of the form z(x) of the solution curve. Use this expression to again determine the maximal height of the shot. Use conservation of energy to determine the maximal height of the shot. You should find the same answer with all three methods.
Expert Solution
steps

Step by step

Solved in 5 steps with 4 images

Blurred answer
Knowledge Booster
Central force
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Glencoe Physics: Principles and Problems, Student…
Glencoe Physics: Principles and Problems, Student…
Physics
ISBN:
9780078807213
Author:
Paul W. Zitzewitz
Publisher:
Glencoe/McGraw-Hill