Ignore work done m = 3The spacing of ruled lines on a diffraction grating is 1830 rum. The grating is illuminated at normal incidencewith a parallel beam of white light in the 400 nm to 700 nm wavelength band. The second order spectrum andthe third order spectrum overlap. The angular width of the overlap is closest to:m = 2A) 6.9°B) 8.9°C) 4.9*D) 5.91830mm1830λ = 400am-700mm..!m=2& m = 3overlapSing, = madsmallest↓›↓d₂ton = X SpoisSino₂-sin, = (3-2)biggestd22.489-12.6The pupil of a cat's eye narrows to a slit of width 0.5 mm in daylight. Assuming a wavelength10 m)of 500 nm, what is the angular resolution? (1 nm =500 x 10distancebetween-91-3mE) 7.911830×10-9

distance between the ruled lines = d = 1838 nm wavelengths = 400 nm and 700 nm

Answered: The spacing of ruled lines or

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The spacing of ruled lines or

University Physics Volume 3

17th Edition

ISBN:9781938168185

Author:William Moebs, Jeff Sanny

Publisher:William Moebs, Jeff Sanny

Chapter4: Diffraction

Section: Chapter Questions

Problem 46P: An electric current through hydrogen gas produces several distinct wavelengths of visible light....

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Special Relativity

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Question

Ignore work done

m = 3
The spacing of ruled lines on a diffraction grating is 1830 rum. The grating is illuminated at normal incidence
with a parallel beam of white light in the 400 nm to 700 nm wavelength band. The second order spectrum and
the third order spectrum overlap. The angular width of the overlap is closest to:
m = 2
A) 6.9°
B) 8.9°
C) 4.9*
D) 5.9
1830mm
1830
λ = 400am-700mm..!
m=2
& m = 3
overlap
Sing, = ma
d
smallest
↓
›
↓
d₂ton = X Spois
Sino₂-sin, = (3-2)
biggest
d
22.489-12.6
The pupil of a cat's eye narrows to a slit of width 0.5 mm in daylight. Assuming a wavelength
10 m)
of 500 nm, what is the angular resolution? (1 nm =
500 x 10
distance
between
-9
1-3m
E) 7.9
1
1830×10-9

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