the steps of Counting Sort (second version that doesn’t use array B as given in the lectures) for the following array A of values with C for counting. A 3 2 5 1 0 7 8 index 1 2 3 4 5 6 7 C 0 0 0 0 0 0 0 0
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Show the steps of Counting Sort (second version that doesn’t use array B as given in the lectures) for the following array A of values with C for counting.
A 3 2 5 1 0 7 8
index 1 2 3 4 5 6 7
C 0 0 0 0 0 0 0 0
index 1 2 3 4 5 6 7 8
Step by step
Solved in 2 steps
- Program in c please. Get array lenght and elements from the user. Print that array in reverse order. Only print array in reverse array don't reverse the arrayNow, write another function that prints the values of any array in reverse order. (The function should not change the original array). As an example, if a [] = {1, 2, 3, 4, 5}; The function would print the values in reverse as: 5, 4, 3, 2, 1Implement the solution using python for the Array Sum problem. Place your code on the space provided below. Include a screenshot of the output
- You are given an array in which every number from 1 to N appears precisely once with the exception of one. How is the missing number to be located in O(N) time and 0(1) space? What if two numbers were absent?Check if Array Elements are Consecutive. Given an array, we need to check if array contains consecutive elements in Python.Write c program . Get array lenght and elements from user. Find sum of all the array elements and print it.
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- Below is the recursive implementation of binary search from lab with one change (in red): the print statement at the top of the function which prints "BOO" There is also a main function which calls bsearchR on the sorted array data[] with 7 elements and searching for 10. QUESTION: How many BOOS will be printed by this program? // Recursive Binary Search Routine that does the "Real" Work int bsearchR(int a[], int lo, int hi, int x) { int m; printf("BO0\n"); // <<<<==== NEW STATEMENT if(hi < lo) return -1; m = (lo + hi) / 2; if(a[m] == x) return m; else if(x < a[m]) return bsearchR(a, lo, m-1, x); else return bsearchR(a, m+1, hi, x); } int main() { int data[] = {5, 8, 12, 15, 20, 25, 30}; int idx = bsearchR(data, e, 6, 10); return 0; }Below is the recursive implementation of binary search from lab with one change (in red): the print statement at the top of the function which prints "BOO" There is also a main function which calls bsearchR on the sorted array data[] with 7 elements and searching for 12. QUESTION: How many BOOS will be printed by this program? // Recursive Binary Search Routine that does the "Real" Work int bsearchR(int a[], int lo, int hi, int x) { int m; printf("BOO\n"); // <<<<==== NEW STATEMENT if(hi < lo) return -1; m = (lo + hi) / 2; if(a[m] == x) return m; else if(x < a[m]) return bsearchR(a, lo, m-1, x); else return bsearchR(a, m+1, hi, x); } int main() { int data[] = {5, 8, 12, 15, 20, 25, 3e}; int idx = bsearchR(data, e, 6, 12); return e; }The solution must be recursive. inputAndPrintReverse:Inputs integers from the user until the user enters 0, then prints the integers in reverse order. For this method, you may NOT use an array or any type of array structure, in other words, you may not use any structure to store the user input.