The switch in the given circuit has been closed for a long time but is opened at t= 0. Determine (t) for t> 0. Assume v¡= 35 V. i(t) H m Vi F 292 ww t=0 The value of i(t) = AeBt C(Dt - E°)u(t) A where A = B = C = (Click to select) D= and E=
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- For which measurement is this oscilloscope time difference reading useful? Oscilloscope-XSC1 Time Channel_A Channel B 89.282 V -91.176 V 250.000 us 169.064 V Reverse -168.880 V -337.944 V 753.788 us T2-T1 503. 788 us -180.458 V Save Ext. trigger Timebase Channel A Channel B Trigger Scale: 200 us/Div Scale: 100 V/Div X pos. (Div): 0 Y/T Add B/A A/B 100 V/Div Edge: F2 AB Ext Scale: Y pos. (Div): 0 Y pos. (Div): 0 Level: AC DC AC 0 DC O Single Normal Auto None SER RI METhe capacitors in the figure are discharged when closing the switch. The switch closes at t = 0.Your University ID has 7 digits: X6X5X4X3X2X1X0Y1 = first digit from right to left (X0, X1, ...) that is different from zero.Y2 = second digit from right to left that is different from zero.Y3 = third digit from right to left that is different from zero.Y4 = fourth digit from right to left that is different from zero.Use the following values for the different components (a) Find the time constant of the circuit.(b) Find the charge on each of the capacitors as a function of time.Hello, I know how to complete the time diagram when PRE and CLR remain HIGH. I don't know what are PRE and CLR, and I can't complete the time diagram when considering PRE and CLR Thanks
- Q2/Find (1101100)2 + (1100111)Ex-3 - (1011011)Gray= ( )Gray O 1010010 O 1100101 O None of them O 1111111 O 1000010 101100011For the D-type latch in the figure, indicate the value of Q at time T5 INDETERMINATE 0 1Find the following signals FT (Hint use FT pairs and FT propertise), Please write procedures (a) P3(t +2)+2P2(t- 1) (b) te-3u (1) +cos3t (c)3P (2t) For the toolbar, press ALT+F10 (PC) or ALT+FN+F10 (Mac). A v In *G白Q BIUS Paragraph Arial 10pt 田田田 EX: x X, T T 网 !!!
- What is the function of the circuit shown in Figure 9? CLR CLK (9) (8) (2) R PR (3) lo S bHR Q₁ S bR bR (5) Q₂ S Figure 9 (6) 23 S PR (10) 24 PR (11) Q5 S PR (12) 26 S (13) 27(inference regarding signals from pole-zero information) Handwrite and step by step solutionsio2 (in ampere) due to 12 only= Oa. 0.9277621122789 Ob. -4.6388105613945 Oc. 2.3194052806973 Od. -2.3194052806973 (Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1) io3 (in ampere) due to 11 only= Oa. 0.14201486798257 Ob. 1.4201486798257 Oc. 0.71007433991284 Od. -0.21302230197385 (Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1) io (in ampere) = (Note that io=i01+io2+io3, where io1 is due to V1, io2 is due to 12 and io3 is due to I1) Power dissipated by R2 (in watt) =
- S1-The waveforms in the figure are applied to D-type FF. Accordingly, draw the shape of the signal received from the Q output according to the following time intervals. (It may be helpful for you to take a time slot for each frame interval in your notebook. Draw the time intervals by showing the number of each interval as below) Set='0' CLK D. Q D type CLK- FF Reset='1' i1i213i 415 i 6i71819 1011121314151611718119120 21122iThe vertical asymptote of the following ... function is 4x2 + 20x + 24 f(x) = x + 3 The answer is not mentioned X=-2 No vertical asymptote X=-3Determine the time constant T1 of circuit R1C1