The thiosulfate ion (S₂032) is oxidized by lodine as follows: 25₂032 (aq) + 1₂(aq) → S406²(aq) + 21 (aq) In a certain experiment, 5.51x10-3 mol/L of S₂0₂2 is consumed in the first 11.0 seconds of the reaction. Calculate the rate of production of iodide ion. mol/L/s

The thiosulfate ion (S₂032) is oxidized by lodine as follows: 25₂032 (aq) + 1₂(aq) → S406²(aq) + 21 (aq) In a certain experiment, 5.51x10-3 mol/L of S₂0₂2 is consumed in the first 11.0 seconds of the reaction. Calculate the rate of production of iodide ion. mol/L/s

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter12: Chemical Kinetics

Section: Chapter Questions

Problem 102CWP: The thiosulfate ion (S2O32) is oxidized by iodine as follows: 2S2O32(aq)+I2(aq)S4O62(aq)+2I(aq) In a...

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Give detailed Solution with explanation (no need Handwritten answer

The thiosulfate ion (S₂032) is oxidized by lodine as follows:
25₂032(aq) + 1₂(aq) → S406²(aq) + 21 (aq)
In a certain experiment, 5.51x103 mol/L of S₂0₂2 is consumed in the first 11.0 seconds of the reaction.
Calculate the rate of production of iodide ion.
mol/L/s

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