The velocity of a car traveling along a straight line is given by v = (4 · ť² − 6 · t) -6-t) ft, where it is in seconds. Initially, s = 4 ft when t = 0. a. Determine the positions of the car when t = 4 s. b. Determine the time t when the car's velocity changes from positive to negative velocity or negative to positive velocity. c. Determine the total distance travelled during the time interval t = 0 s to t = 4 s. d. Determine the acceleration a at t = 3 s. Round your final answers to 3 significant digits/figures. ) ft 8 = ( time = ( total distance = ( a = ( ) s ft 8² ) ft

The velocity of a car traveling along a straight line is given by v = (4 · ť² − 6 · t) -6-t) ft, where it is in seconds. Initially, s = 4 ft when t = 0. a. Determine the positions of the car when t = 4 s. b. Determine the time t when the car's velocity changes from positive to negative velocity or negative to positive velocity. c. Determine the total distance travelled during the time interval t = 0 s to t = 4 s. d. Determine the acceleration a at t = 3 s. Round your final answers to 3 significant digits/figures. ) ft 8 = ( time = ( total distance = ( a = ( ) s ft 8² ) ft

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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