The volume of a sphere is increasing at a constant rate of 198 cubic feet per second. At the instant when the volume of the sphere is 18 cubic feet, what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V = 3r³ and the surface area can be found with S = 47². Round your answer to three decimal places (if necessary).

The volume of a sphere is increasing at a constant rate of 198 cubic feet per second. At the instant when the volume of the sphere is 18 cubic feet, what is the rate of change of the surface area of the sphere? The volume of a sphere can be found with the equation V = 3r³ and the surface area can be found with S = 47². Round your answer to three decimal places (if necessary).

Calculus For The Life Sciences

2nd Edition

ISBN:9780321964038

Author:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher:GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Chapter6: Applications Of The Derivative

Section6.4: Related Rates

Problem 28E: LIFE SCIENCE APPLICATION Water Level A trough has a triangular cross section. The trough is 6 ft...

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