This code check whether a number is divisible by 5 and 11 or not. *

C++ Programming: From Problem Analysis to Program Design
8th Edition
ISBN:9781337102087
Author:D. S. Malik
Publisher:D. S. Malik
Chapter8: Arrays And Strings
Section: Chapter Questions
Problem 21PE
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This code check whether a
number is divisible by 5 and 11 or
not. *
1-....
2-.
3-...
4-.
1-lf ((n Mod 5 = 0) And (n Mod 11 = 0))
O Then 2-Print "divisible" 3-Else 4-Print "not
%3D
divisible"
1-lf ((n Mod 5 = 0) And (n Mod 11 = 0))
%3D
Then 2-Print "not divisible" 3-Else 4-Print
divisible"
1-lf ((n Mod 5 = 0) And (n Mod 11 =
O Then 2-Print "divisible" 3-Elseif 4-Print
%3D
"not divisible"
1-lf ((n / 5 = 0) And (n / 11 = 0)) Then 2-
O Print "divisible" 3-Else 4-Print "not
%3D
divisible"
1-lf (n / 5 = 0) Or (n / 11 = 0)) Then 2-
%3D
Print "divisible" 3-Else 4-Print "not
divisible"
1-lf ((n / 5 = 0) Not (n / 11 = 0)) Then 2-
O Print "divisible" 3-Else 4-Print "not
divisible"
Transcribed Image Text:This code check whether a number is divisible by 5 and 11 or not. * 1-.... 2-. 3-... 4-. 1-lf ((n Mod 5 = 0) And (n Mod 11 = 0)) O Then 2-Print "divisible" 3-Else 4-Print "not %3D divisible" 1-lf ((n Mod 5 = 0) And (n Mod 11 = 0)) %3D Then 2-Print "not divisible" 3-Else 4-Print divisible" 1-lf ((n Mod 5 = 0) And (n Mod 11 = O Then 2-Print "divisible" 3-Elseif 4-Print %3D "not divisible" 1-lf ((n / 5 = 0) And (n / 11 = 0)) Then 2- O Print "divisible" 3-Else 4-Print "not %3D divisible" 1-lf (n / 5 = 0) Or (n / 11 = 0)) Then 2- %3D Print "divisible" 3-Else 4-Print "not divisible" 1-lf ((n / 5 = 0) Not (n / 11 = 0)) Then 2- O Print "divisible" 3-Else 4-Print "not divisible"
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