To compute the solubility product (Ksp) of barium nitrate (Ba(NO3)2), an excess amount of Ba(NO3)2 was added to 2 liters of water at 25 degrees celcius until the solution is saturated. Ba(NO3)2 is only slightly soluble in water. It was observed in their experiments that the solution boils at 100.15 K. Barium nitrate dissociates via the process: ?a(NO3)2(s) ⇄ Ba2+(aq) + 2NO3- (aq) Ksp = [Ba2+][NO3-]2 What is the solubility product Ksp and vapor pressure of the solution?

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