TReview lopicS] TRelerences Nitrogen dioxide, NO2, decomposes upon heating to form nitric oxide and oxygen according to the following equation: 2NO2 (9) → 2NO(9) + O2 (g) At the beginning of an experiment, the concentration of nitrogen dioxide in a reaction vessel was 0.1103 mol/L. After 69.0 s, the concentration decreased to 0.1067 mol/L. What is the average rate of decomposition of NO2 during this time interval in mol/(L-s)? Average rate = mol/(L-s)

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Chapter4: Stoichiometry
Section: Chapter Questions
Problem 4.87PAE
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TReview TopicS]
TReferences
Nitrogen dioxide, NO2, decomposes upon heating to form nitric oxide and oxygen according to
the following equation:
2NO2 (g) → 2NO(g) + O2 (g)
At the beginning of an experiment, the concentration of nitrogen dioxide in a reaction vessel was
0.1103 mol/L. After 69.0 s, the concentration decreased to 0.1067 mol/L. What is the average
rate of decomposition of NO2 during this time interval in mol/(L·s)?
Average rate =
mol/(L-s)
Transcribed Image Text:TReview TopicS] TReferences Nitrogen dioxide, NO2, decomposes upon heating to form nitric oxide and oxygen according to the following equation: 2NO2 (g) → 2NO(g) + O2 (g) At the beginning of an experiment, the concentration of nitrogen dioxide in a reaction vessel was 0.1103 mol/L. After 69.0 s, the concentration decreased to 0.1067 mol/L. What is the average rate of decomposition of NO2 during this time interval in mol/(L·s)? Average rate = mol/(L-s)
For the rearrangement of ammonium cyanate to urea in aqueous solution at 50 °C
NH4NCO(NH2)2CO
the following data have been obtained:
[NH4NCO], M 0.973
0.407
0.257
0.187
time, min
130
260
390
%3D
The average rate of disappearance of NH,NCO over the time period from t = 130 min tot =
260 min is
M min 1.
Transcribed Image Text:For the rearrangement of ammonium cyanate to urea in aqueous solution at 50 °C NH4NCO(NH2)2CO the following data have been obtained: [NH4NCO], M 0.973 0.407 0.257 0.187 time, min 130 260 390 %3D The average rate of disappearance of NH,NCO over the time period from t = 130 min tot = 260 min is M min 1.
Expert Solution
Step 1

given

Initial concentration of nitrogen dioxide (NO2)

= 0.1103 mol/L

Final concentration of NO2

= 0.1076 mol/L

Time taken = 65.0 s

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