trickling filters.
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- 12.60 The aeration tank for a completely mixed aeration process is being sized for a design waste- water flow of 7500 m³/d. The influent BOD is 130 mg/l with a soluble BOD of 90 mg/l. The design effluent BOD is 20 mg/l with a soluble BOD of 7.0 mg/l. Recommended design para- meters are a sludge age of 10 d and volatile MLSS of 1400 mg/l. Selection of these values takes stants from a bench-scale treatability study are Y into account the anticipated variations in wastewater flows and strengths. The kinetic con- 0.60 mg VSS/mg soluble BOD and k₁ = 0.06 per day. Calculate the volume of the aeration tank, aeration period, food ganism ratio, and excess biomass thA secondary clarifier handles a total flow of 9600 m³/d from the aeration tank of a conventional activated-sludge treatment system. The concentration of solids in the flow from the aeration tank is 3000 mg/l. The clarifier is required to thicken the solids to 12000 mg/l, and hence it is to be designed for a solid flux of 3.2 kg/m²h. The surface area of the designed clarifier for thickening (in m², in integer)Example (Activated Sludge Process) - Completely Mixed with Recycle A completely mixed activated sludge process, treating a municipal wastewater, has a primary clarifier effluent BOD, of 135 mg/L. The design MLSS is 3590 mg/L, and the MLVSS is 80% of the MLSS. The plant permit is for an effluent BOD, of 20 mg/L and 20 mg/L suspended solids. The effluent suspended solids have a BOD, of 0.65 mg BOD, / mg suspended solids. The underflow solid concentration (MLVSS) is 10,000 mg/L. If umax = 3.0 day, Ks 60 mg/L, Y= 0.50 mg MLVSS / mg BOD, removed, ka= 0.1 day, and the influent flow is 0.25 m/sec, determine the following: 1. The required reactor detention time, 0. 2. The reactor basin volume, V, in m³. 3. The net waste activated sludge produced each day (kg/day). 4. The mass of solids (both volatile and inert) to be wasted each day (kg/day). The return sludge flow rate the recycle ratio. 6. The F/M ratio. 7 June 2021 Dr. Dawood Eisa Sachit Biological Wastewater Treatment 47
- Question 30 In activated sludge system, SRT is governed by O HRT sludge wastage aerationQuestion 1 (1) The aerobic degradation and the conversion of dissolved wastewater pollutants take place in fixed-bed processes such as trickling filter systems. (a) Name two (2) different filler materials used in trickling filters. (b) List two (2) advantages and disadvantages each of the media used in the above (a) systems. (c) What is the difference between primary and secondary clarifiers?You are to design a single-stage, stone-media trickling filter for the treatment of 0.5 mgd wastewater containing 170 mg/L of settled BOD. The plant is located in a warm climate and the minimum wastewater temperature is 16°C. Using a recirculation ratio of 0.5, what is the minimum volume required to achieve an average effluent BOD of no more than 30 mg/L? Determine the diameter if the filter media is 5 ft. Is the hydraulic loading acceptable?
- 4. All D- Activated sludge process consists of: 1. Aeration tank 2. Sedimentation tank 3. Aeration and sedimentation tankThe town of Gatesville has been directed to upgrade its primary WWTP to a secondary plant that can meet an effluent standard of 30.0 mg/L BOD5 and 30.0 mg/L suspended solids (SS). They have selected a completely mixed activated sludge system. Assuming that BOD5 of the SS may be estimated as equal to 57 percent of the SS concentration, estimate the required volume of the aeration tank. The following data are available from the existing primary plant. Existing plant effluent characteristics Flow =0.150 m3/s BOD5 =82.0 mg/L Assume the following values for the growth constants: Ks= 100 mg/L BOD5; µm =2.5 d-1; kd =0.050 d-1; Y = 0.50 mg VSS/ mg BOD5 removed. Assume the concentration of MLVSS is 2000 mg/L.2. A scrubber separator is used to remove sulfur dioxide (SO2) from a gas stream. A 0.5 m'/sec inlet stream (350 K, 1 atm) contains 1.2 ppmv SO2. Find the required removal efficiency if the cleaned outlet stream must contain no more than 240 µug/scm.
- A completely mixed activated sludge process is being designed for a wastewater flow of 3 MGD using kinetic equations. The influent BOD of 180 mg/L is essentially all soluble and the design effluent soluble BOD is 10 mg/L. The mean cell residence time is selected to be 8.0 days for sizing the aeration volume tank, and the MLVSS is 2500 mg/L. The kinetic constants from a bench-scale treatability study are Y = 0.60 Ib VSS/Ib BOD and Kd = 0.06 day-1. ---Determine the efficiency of soluble BOD removal. For this, you will have to recognize substrate concentration in the coming flow (So) and the concentration of substrate in the exiting flow (Se).Name:.. 11. An activated sludge system has a single aeration basin with a volume of 300,000 gal and 2 - 25 ft. diameter secondary clarifiers. The influent flow is 1.1 MGD, and the influent BODs and TSS are 170 mg/L and 190 mg/L, respectively. The mixed liquor suspended solids concentration is 2500 mg/L, and the recycle suspended solids concentration is 6800 mg/L. The sludge recycle flow rate is 0.60 MGD and the solids residence time is 9 days. 10a. Calculate the volumetric BODs loading rate on the aeration basin in units of lbs/1000 ft³-d. ( 10b. Calculate the F:M ratio in units of g-BODs/g-TSS-d 9a) Calculate the organic loading rate of the trickling filter in lb BOD/day/1000 ft3 with the data below. b) What kind of media filter is used in the above question (2a)? Justify your decision. Diameter of TF 60 feet Depth of Media 15 feet Influent Flow 1.5 mgd Influent BOD 150 mg/L