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- The force F has a magnitude of 600 Ib and acts along the line AM where M is the midpoint of the vertical side OB of the parallelepiped. Express Fas its magnitude times the appropriate unit vector and then determine its x-, y-, and z-scalar components. |18" M F = 600 lb !! A 12" 15" Answers: Vector F= (600 Ib)( i i+ i j+ i k) Scalar components Fx i Ib Fy = i Ib E. = IbThe force F has a magnitude of 640 lb and acts along the line AM where M is the midpoint of the vertical side OB of the parallelepiped. Express F as its magnitude times the appropriate unit vector and then determine its x-, y-, and z-scalar components. |13" M F = 640 lb 7" 14" Answers: Vector F = (640 lb)( i i+ i j+ i k) Scalar components Fx = Ib Fy Fz i IbThe force F has a magnitude of 600 lb and acts along the line AM where M is the midpoint of the vertical side OB of the parallelepiped. Express F as its magnitude times the appropriate unit vector and then determine its x-, y-, and z-scalar components. |18" M F = 600 lb 12" 15" Answers: Vector F= (600 lb)( i i+ i j+ k) Scalar components Fx = i Ib Fy= i Ib Fz = i Ib
- Determine a unit vector parallel to the resultant vector of 2i + 9j – 9k lb, – 2i – 6j + 8k lb, and - 2i + 6j + 4k lb. i + V X k) lb R = ( -0.206 0.92 j+ | 0.3What is the component of the force vector G = (3.0i + 4.0j + 10.0k )N along the force vector H = (1.0i + 4.0j )N ?Two vectors are given by a = 8.31 + 8.4j and B = 1.lî + 3.5). Find (a) a x ») a - ( a + 3) -. and (d) the component of a along the direction of b ? (a) Number Units N (b) Number Units kg This answer has no units m (c) Number Units i m/s (d) Number i Units
- The magnitude of the force F is 780 Ib. Express F as a vector in terms of the unit vectors i and j. Identify both the scalar and vector components of F. Y, ft F = 780 Ib | --x, ft 36° A (7,-3) Answers: Vector expression: F = 5) Ib + Scalar components: Fx = Ib, Fy Ib Vector components: Fx = i lb, Fy = j lbConsider the two force vectors D = (2.87 N)i + (-4.35 N)j + (1.93 N)k and F = (2.3 N)i + (4.18 N)j + ak.The magnitude of the force F is 720 Ib. Express F as a vector in terms of the unit vectors i and j. Identify both the scalar and vector components of F. Y, ft F = 720 Ib | -x, ft |_ 33° A (6,-1) Answers: Vector expression: F = (L 5) Ib the tolerance is +/-2% Scalar components: Fx = |Ib, Fy = Ib Vector components: Fx |i lb, Fy = Ib
- Given the following vectors, A = -2.00i+ 4.005 -6.00k B= 5.00j+2.00A Č =-3.008 (a) Find A, B, and C. (b) FindD=C+2B. (c) Find E= 3A- 20. (d) Calculate D. (c) Calculate E. (f) Find the directional angle 0 of D and E.The resultant of 3 vectors is equal to 23 units, 11 W of N. The added vectors are as follows: A - 27 units, 18 N of E, B-25 units, 19 W of S and unknown vector C. Determine the magnitude and direction of vector C.Two forces of F₁ = 112 √2 N and F₂ = 388 √2 What is the resultant force in terms of the force vectors F₁ and F2? What is the magnitude of an equal and opposite force, F3, which balances the first two forces? sin() cos() tan() T HOME cotan() acos EM4 asin() atan() acotan() sinh() 7 8 9 5 6 1 2 3 * 0 END cosh() tanh() cotanh() ⒸDegrees O Radians VO BACKSPACE DEL CLEAR Submit Hint Feedback I give up! Given your observations from parts a and b, if working with vectors in 3 dimensions (i, j, k); what will the normalizing term n be for (i- j+ k) (i − j+ k) the two vectors F₁ = C₁ N and F₂ = 0₂ N. √T | Fren | Given the normalizing term n found in the previous part in 3 dimensions (i, j, k); what will the magnitude of the resultant vector be in terms of the constants c₁ and ₂. (i − j+ k) (i- j+k) The vectors in question are F₁: N and F₂ = 0₂ √√T √π F3 = = C1 N act on an object.