Two machines are evaluated for a new project. described in the following table. Determine EUAC for both alternatives and determine the best option. Purchase cost Salvage value Duration Machine A Machine B $10,000 $15,000 $1,250 $1,950 5 years 10 years
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- From the given values below, which machine should be selected using (a) Present worth Method and (b) Future worth Method if interest rate is 10% per year? Machine A B Initial Cost (Php) Annual Operating Cost 146,000 15,000 80,000 10,000 3 220,000 10,000 75,000 25,000 Annual Revenue Salvage Value Useful Life (years) 6Compare the machines below using present worth analysis at i10% per year and find which one should be selected Machine Y First Cost Operating Cost Savage Lfe cycle Machine X 20.000 3.000 3.000 3years Firat Cost 30.000 .000 Annuel Operating Cost Salvage Life cycle 3.000 6 yoarsThree machines are being considered for purchase. If the interest rate is 10%, which machine should be bought? a) Select the best alternative using annual worth analysis. b) Select the best alternative using present worth analysis. A B CInitial cost 150000 210000 300000 Annual operating cost 20000 15000 8000 Repairs will have to be made every 5 years 20000 50000 38000 Salvage value 40000 60000 80000 Useful life 10 years 15 years 20 years
- 1. Two alternatives are being considered for installation. Which should be selected based on a present worth comparison at an interest rate of 6% per year. Alternative A Alternative B First Cost, $ 17,650 22,900 Maintenance Cost, $/year 1700 1400 Salvage value, $ 10,500 17,000 Life, years 4 3You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 13% per year? Why is yours the correct choice? Alternative First Cost X $-45,000 Maintenance cost, per $-9000 Year Salvage Value $1,000 Life 5 years Y $-55,000 $-4000 $6,500 5 years The present worth of alternative X is $ 13888 and that of alternative Y is $ 44459.4 Alternative X is selected by the company.Check whether the project is accepted or rejected and recommend the best project, MARR=6% and n=8 years, using Payback period, ROI, NPV, Aw, IRR methods. ID Project I Project II increase Annual Initial Annual cost revenues initial Annual Salvage value annual salvage value running in cost revenues maintenance revnues cost 1910095 280000 60000 2000 28000 400000 72000 2000 40000 12000
- Q1: For the machines indicated below. Consider i= 10% per year First cost Annual cost Salvage value Life duration Machine A 20,000 $ 5,000 $ 7,500 $ 3 Machine B 25,000 4,000 6,000 4 A- Draw cash flow diagram for each machine for one cycle of each project B- Draw cash flow diagram for each project considering the LCM life cycle (Hint: different project duration, need to have the LCM life cycle) C- Compare the machines to select best alternative one based on Present worth analysis method D- Repeat part B considering Future worth analysisDetermine the B/C ratio for the following project. First Cost P100, 000 Project life, years 5 Salvage value P10, 000 Annual benefits Р60, 000 Annual O and M Р22, 000 Interest rate, % 15You have been asked to evaluate two alternatives, X and Y, that may increase plant capacity for manufacturing high-pressure hydraulic hoses. The parameters associated with each alternative have been estimated. Which one should be selected on the basis of a present worth comparison at an interest rate of 10% per year? Why is yours the correct choice? Alternative First Cost Maintenance cost, per Year Salvage Value Life X $-25,000 $-8000 $1,000 5 years Y $-55,000 $-2000 $2,000 5 years and that of alternative Y is $1 The present worth of alternative X is $. Alternativ (Click to select) is selected by the company.
- Use annual worth analysis to decide on which machine to buy for a project that will last 8 years. Machine X Machine Y 2 3 S 0 4 X First Cost, $ 20,000 14,000 Year 1 AOC, $ Year 2 AOC, S 5,000 20000 4000 4000 Year 3 AOC, $ 3,000 5,000 Year 4 AOC, S 4,000 5,000 Year 5 AOC, $ 4,000 6,000 Year 6 AOC, S 5,000 Year 7 AOC, S 4,000 Salvage Value in 3,000 Year 8, S 14000 3000 3000 5000 Sood 6000 5000 7 3000 4000 2⁰0A firm is trying to decide which of two machines to purchase as described in in the table below. Using the interest rate 9% or 0.09, use present worth analysis to determine which machine, if either, should be purchased. Show all your work. Machine: A - B First Cost: $800 - $600 Annual Net Benefit: $130 - $230 Salvage Value: $40 - $20 Usefil Life (years): 9 - 3A firm is considering three mutually exclusive alternatives as a part of an upgrade to an existing transportation network. If the MARR is 10% per year, which alternative(if any) should be chosen using the IRR analysis procedure? Use trial & error and show your calculations. A B C Initial Cost 40000 30000 20000 Annual Revenue 10400 8560 7750 Annual Cost 4000 3000 2500 Salvage Value 3000 2500 2000 Useful Life 20 20 10