Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 26.3 with a standard deviation of 5.2, while the 200 students in group 2 had a mean score of 17.6 with a standard deviation of 2.8. Complete parts (a) and (b) below. (a) Determine the 90% confidence interval for the difference in scores, μ1−μ2. Interpret the interval. The lower bound is nothing. The upper bound is nothing.
Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The 200 students in group 1 had a mean score of 26.3 with a standard deviation of 5.2, while the 200 students in group 2 had a mean score of 17.6 with a standard deviation of 2.8. Complete parts (a) and (b) below. (a) Determine the 90% confidence interval for the difference in scores, μ1−μ2. Interpret the interval. The lower bound is nothing. The upper bound is nothing.
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section11.4: Collecting Data
Problem 3E
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Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. The students in group 1 were asked to spend 5 minutes thinking about what it would mean to be a professor, while the students in group 2 were asked to think about soccer hooligans. These pretest thoughts are a form of priming. The
200 students in group 1 had a mean score of 26.3 with a standard deviation of 5.2, while the 200 students in group 2 had a mean score of
17.6 with a standard deviation of 2.8.
Complete parts (a) and (b) below.(a) Determine the
90%
confidence interval for the difference in scores,
μ1−μ2.
Interpret the interval.The lower bound is
nothing.
The upper bound is
nothing.
(Round to three decimal places as needed.)
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