Two springs were attached in a series as shown. The maximum Shearing stress of he spring is limited to 200MN/m?. G = 80 GPa. determine the maximum load it can carry, total elongation and spring constant.
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- The strength-to-weight ratio of a structural material is defined as its load-carrying capacity divided by its weight. For materials in tension, use a characteristic tensile stress obtained from a stress-strain curve as a measure of strength. For instance, either the yield stress or the ultimate stress could be used, depending upon the particular application. Thus, the strength-to-weight ratio RS/Wfor a material in tension is defined as Rs/w= in which a is the characteristic stress and 7 is the weight density. Note that the ratio has units of length. Using the ultimate stress Uas the strength parameter, calculate the strength-to-weight ratio (in units of meters) for each of the following materials: aluminum alloy 606I-T6, Douglas fir (in bending}, nylon. structural steel ASTM-A57.2, and a titanium alloy. Obtain the material properties from Tables [-1 and 1-3 of Appendix I. When a range of values is given in a table, use the average value.Three round, copper alloy bars having the same length L but different shapes are shown, in the figure. The first bar has a diameter d over its entire length, the second has a diameter d over one-fifth of its length, and the third has a diameter d over one-fifteenth of its length. Elsewhere, the second and third bars have a diameter Id. All three bars are subjected to the same axial load P. Use the following numerical data: P = 1400 kN, L = 5m,d= 80 mm, E= 110 GPa. and v = 0.33. (a) Find the change in length of each bar. (b) Find the change in volume of each bar.Solve the preceding problem if the cross- sectional dimensions are b = 1.5 in. and h = 5.0 in., the gage angle is ß = 750, the measured strains are = 209 × 10-6 and B = -110 × 10, and the material is a magnesium alloy with modulus E = 6.0 X 106 psi and Poisson’s ratio v = 0.35.
- Solve the preceding problem if the thickness of the steel plate is. t = 12 mm. the gage readings are x = 530 × 10-6 (elongation) and y = -210 -× l0-6 (shortening), the modulus is E = 200 GPa, and Poisson’s ratio is v = 0.30.A light helical spring is fabricated by wrapping ¾ -in diameter wire around a forming cylinder 10 inches in diameter. How many number of turns are required to allow an elongation of 3.5 inches. The shearing stress is limited to 18 ksi. Use G = 12 x 106 psi. Answer: n = 5 turnsEHide bl OP=287 N OP=573 N Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.998 mm. determine the applied force F. Select one: OF=10472 N OF=15708 N OF=6283 N O F= 4189N F = 13090 N OF= 5236 N Finish attempt.. US ACTIVITY O Test-Spring 2020-2021 Jump to...
- A heavy-duty helical spring is to be made by wrapping a steel rod 10.6 mm in radius aroundforming cylinder 141 mm in diameter. If the elongation and shearing stress are limited to 161mm and 141 MPa, respectively. How many turns are required approximately? G = 83 GPa. Useapproximate formula for shear stressIf a solid circular rod having an initial diameter D = 0.03 m and initial length L = 0.8 m, is subjected to a tensile force F = 300 kN, the new diameter will be: Given: The rod is made of steel having Young's modulus E = 200 Gpa and a Poisson's ratio = 0.3. Select one: a. Df= 2.993 mm Ob. Df = 10.92 mm Oc. Df= 3.007 mm Od. Df = 30.02 mm Oe. Df = 29.98 mmUse the graphical method to construct the shear-force diagram and identify the magnitude of the largest shear force (consider both positive and negative). The ground reactions at the wall of the cantilever are provided. L₁= 14.75 ft L₂ = 7.75 ft Vc = 91.50 kips Mc = 706.4375 kip-ft 20 kips 6 kips/ft L₁ 103.50 kips 68.50 kips 91.50 kips O 79.50 kips O 114.50 kips 70 kips BO 12 kips/ft L2 O Vc Mc
- 1. A circular shaft with a keyway can be approximated by the section shown in Fig. r=b Ay r r=2acose Figure 1: Circular shaft with a keyway. The keyway is represented by the boundary equation r = b and the shaft is represented by the boundary equation r = 2a cos 0. Show that using a Prandtl stress function of the form ²) (₁ (1-2a cos) X v = K (b² − ²) (1 – : will solve the problem of torsion on this shaft and find the constant K (assume an applied torque T). Compute the shear stress components Txz and Tyz. (Hint: start by converting the stress function to Cartesian coordinates).O P = 287 N OP= 597 N Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one: O F = 13090 N OF= 15708 N OF=4189N F = 5236 N OF= 10472 N O F= 6283N 10:29 EN 4/15/2 TOSHIBAClear my choice Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E= 200 Gpa and a Poisson's ratio of 0.3. If a tensile force Fis subjected to that rod cross-section, the diameter becomes 3.995 mm. determine the applied force F. Select one: O F= 5236 N OF=15708N O F= 13090 N OF=10472 N OF=4189 N O F=6283 N Clear my choice Finish attempt NEXT ACTIVITY MENG360 Test -Spring 2020-2021 Jup to