Under certain reaction conditions, 2,3-dibromobutane reacts with twoequivalents of base to give three products, each of which contains twonew π bonds. Product A has two sp hybridized carbon atoms, product Bhas one sp hybridized carbon atom, and product C has none. What arethe structures of A, B, and C?

Under certain reaction conditions, 2,3-dibromobutane reacts with twoequivalents of base to give three products, each of which contains twonew π bonds. Product A has two sp hybridized carbon atoms, product Bhas one sp hybridized carbon atom, and product C has none. What arethe structures of A, B, and C?

Organic Chemistry

9th Edition

ISBN:9781305080485

Author:John E. McMurry

Publisher:John E. McMurry

Chapter14: Conjugated Compounds And Ultraviolet Spectroscopy

Section14.SE: Something Extra

Problem 65AP: The double bond of an enamine (alkene + amine) is much more nucleophilic than a typical alkene...

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Under certain reaction conditions, 2,3-dibromobutane reacts with two equivalents of base to give three products, each of which contains two new p bonds. Product A has two sp hybridized carbon atoms, product B has one sp hybridized carbon atom, and product C has none. What are the structures of A, B, and C?
Compound A exhibits a peak in its 1H NMR spectrum at 7.6 ppm, indicating that it is aromatic. (a) How are the carbon atoms of the triple bonds hybridized? (b) In what type of orbitals are the π electrons of the triple bonds contained? (c) How many π electrons are delocalized around the ring in A?
The double bond of an enamine (alkene + amine) is much more nucleophilic than a typical alkene double bond. Assuming that the nitrogen atom in an enamine is sp2hybridized, draw an orbital picture of an enamine, and explain why the double bond is electron-rich.
Compounds A and B are isomers having molecular formula C5H12. Heating A with Cl2 gives a single product of monohalogenation, whereas heating B under the same conditions forms three constitutional isomers. What are thestructures of A and B?
Cyclopentadiene is unusually acidic for a hydrocarbon. Which of the following explains why that is? The carbon atoms of cyclopentadiene are all sp hybridized. A В Cyclopentadiene is aromatic. Removal of a proton from cyclopentadiene yields an C aromatic anion. Removal of a hydrogen atom from cyclopentadiene yields a highly stable free radical. D Removal of a hydride ion from cyclopentadiene produces an E aromatic cation. H H. cyclopentadiene
Which compound has conjugated C=C bonds? А. С. D. B.
How many rings and π bonds are contained in compounds A—C? Draw one possible structure for each compound. a.Compound A has molecular formula C5H8 and is hydrogenated to a compound having molecular formula C5H10. b.Compound B has molecular formula C10H16 and is hydrogenated to a compound having molecular formula C10H18. c.Compound C has molecular formula C8H8 and is hydrogenated to a compound having molecular formula C8H16.
How many rings and π bonds are contained in compounds A–C? Draw one possible structure for each compound. a. Compound A has molecular formula C5H8 and is hydrogenated to a compound having molecular formula C5H10.b. Compound B has molecular formula C10H16 and is hydrogenated to a compound having molecular formula C10H18.c. Compound C has molecular formula C8H8 and is hydrogenated to a compound having molecular formula C8H16.
Rank the compounds in each group in order of increasing reactivity in electrophilic aromatic substitution: (a) C6H6, C6H5Cl, C6H5CHO; (b) C6H5CH3, C6H5NH2, C6H5CH2NH2.
Dehydrohalogenation of 1-chloro-1-methylcyclopropane affords two alkenes (A and B) as products. Explain why A is the major product despite the fact that it contains the less substituted double bond.
When alkyne A is treated with NaNH2 followed by CH3I, a product havingmolecular formula C6H10O is formed, but it is not compound B. What isthe structure of the product, and why is it formed?
| Anthracene readily undergoes a Diels-Alder reaction with tetracyanoethene, even though anthracene is NC CN ? + aromatic. NC CN (a) Draw two possible products that can form from this reaction. (b) Explain why anthracene can readily undergo a Diels-Alder reaction, whereas benzene does not.