Use the given information to calculate the enthalpy of reaction for the following reaction: P4010 (S) + 6PCls (s) → 10C3PO (g) (1) P4 + 6Cl₂ → 4 PCI3 (2) P4 +502 P4010 (3) PCl3 + Cl2 → PCIs (4) PCl3 + ½/202 → Cl3PO ΔΗ°= - 1272 kJ ΔΗ°= - 2915 kJ ΔΗ°= -125 kJ AH = -267 kJ

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