EXAMPLE 9.5Oil and WaterGOAL Calculate pressures created by layers of different fluids.AirPROBLEM In a huge oil tanker, salt water has flooded an ol tankto a depth of hz = 5.00 m. On top of the water is a layer of oill k, =Oilby8.00 m deep, as in the cross-sectional view of the tank in thefigure. The ol has a density of 0.700 g/cm3. Find the pressure atthe bottom of the tank. (Take 1,025 kg/m³ as the density of saltWaterwater.)STRATEGY P= P, + pgh must be used twice. First, use it to calculate the pressure P, at the bottom ofthe oil layer. Then use this pressure in place of Po in the equation and calculate the pressure Phot at thebottom of the water layer.SOLUTIONUse the equation to calculate thepressure at the bottom of the oil layer.(1)P1 - Po + egh,= 1.01 x 105 Pa+ (7.00 x 10° kg/m) (9.80 m/s)(8.00 m)P1 - 1.56 x 105 PaNow adapt the equation to the new(2) Poot - P, + pgh,starting pressure, and use it tocalculate the pressure at the bottom of= 1.56 x 105 Pa+ (1.025 x 10° ka/m?) (9.80 m/s?) (s.00 m)the water layer.Poot - 2.06 x 10° PaLEARN MOREREMARKS The weight of the atmosphere results in Pg at the surface of the oil layer. Then the weight ofthe oil and the weight of the water combine to create the pressure at the bottom.QUESTION Why does air pressure decrease with increasing altitude? (Select all that apply.)DiThe weight of the air below is smaller.There is more air below to push up more strongly.O Colder air is less dense.O Hot air rises.Less air above pushes down.O The weight of the air above is smaller.PRACTICE ITUse the worked example above to help you solve this problem. In a huge oil tanker, salt water has floodedan oil tank to a depth of hz = 4.70 m. On top of the water is a layer of oil k, = 8.15 m deep, as in thecross-sectional view of the tank as shown in the figure. The oill has a density of 0.700 g/cm?. Find thepressure at the bottom of the tank. (Take 1,025 kg/m as the density of salt water.)РаEXERCISEHINTS: GETTING STARTED | "'M STUCK!Calculate the pressure on the top lid of a chest buried under 3.50 meters of mud with density1.75 x 10 kg/m at the bottom of a 12.5-m-deep lake.Ра

Answered: Image /qna-images/answer/5418e7b7-6b45-4593-a3fe-66171a4611e7.jpg

Use the worked example above to help you solve this problem. In a huge oil tanker, salt water has flooded an oil tank to a depth of hz - 4.70 m. On top of the water is a layer of oil h, - 8.15 m deep, as in the cross-sectional view of the tank as shown in the figure. The oll has a density of 0.700 g/cm. Find the pressure at the bottom of the tank. (Take 1,025 kg/m as the density of salt water.) | Pa EXERCISE HINTS: GETTING STARTED I I'M STUCK! Calculate the pressure on the top lid of a chest buried under 3.50 meters of mud with density 1.75 x 10' ka/m at the bottom of a 12.5-m-deep lake. Pa

Use the worked example above to help you solve this problem. In a huge oil tanker, salt water has flooded an oil tank to a depth of hz - 4.70 m. On top of the water is a layer of oil h, - 8.15 m deep, as in the cross-sectional view of the tank as shown in the figure. The oll has a density of 0.700 g/cm. Find the pressure at the bottom of the tank. (Take 1,025 kg/m as the density of salt water.) | Pa EXERCISE HINTS: GETTING STARTED I I'M STUCK! Calculate the pressure on the top lid of a chest buried under 3.50 meters of mud with density 1.75 x 10' ka/m at the bottom of a 12.5-m-deep lake. Pa

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter15: Fluid Mechanics

Section: Chapter Questions

Problem 46P

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