BAKCL @node A6.13A = I₂+I6q @KCL @node B12A + 7 = 167.0312A = Ibn-Iza @#²KVL @ Loop 1-V₁ 7 √√3+√√₂ =0- (20) 1₂0 + (6) Fon + (7) ₂=0-21 +61 + 1 =+I₂ = -2AHIar = GAIz = -6AUke systems of treat equations (useCalculator for shortcut)12A√ V₁ = 2^(-3A)|V₁ = - GVV₁ = 7 (-6A)[√₂ = -42VV₂- 62 (6A)V₂ = 36VExplainto me howthe process

Answered: - V₁ 7 √√3+√√₂ =0 - (20) 1₂a + (65) Fon…

- V₁ 7 √√3+√√₂ =0 - (20) 1₂a + (65) Fon + (7) ₁₂ = 0 20 -62 F.A 7.02 -212 +61 + 710 =0 @ + Uke systems of breat equations (use Calculator for shortcut) I₂e = -2A //

Electricity for Refrigeration, Heating, and Air Conditioning (MindTap Course List)

10th Edition

ISBN:9781337399128

Author:Russell E. Smith

Publisher:Russell E. Smith

Chapter7: Alternating Current, Power Distribution, And Voltage Systems

Section: Chapter Questions

Problem 7RQ

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Concept explainers

Fourier Series

Most of the incidents studied in the field of Engineering and Science as a function of time. For example, current and voltage are in the alternating current circuit. These occasional activities can be analyzed in the activity components (fundamental frequency and harmonics) through a process called Fourier analysis.

Question

BA
KCL @node A
6.1
3A = I₂+I6q @
KCL @node B
12A + 7 = 16
7.03
12A = Ibn-Iza @
#²
KVL @ Loop 1
-V₁ 7 √√3+√√₂ =0
- (20) 1₂0 + (6) Fon + (7) ₂=0
-21 +61 + 1 =
+
I₂ = -2A
H
Iar = GA
Iz = -6A
Uke systems of treat equations (use
Calculator for shortcut)
12A
√ V₁ = 2^(-3A)
|V₁ = - GV
V₁ = 7 (-6A)
[√₂ = -42V
V₂- 62 (6A)
V₂ = 36V
Explain
to me how
the process

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