valsTable: o 50 1 51 2 3 4 5 6 7 8 9 st 67 Empty-since-start Empty-after-removal Occupied Hash table valsTable uses linear probing and a hash function of key % 10. HashInsert(valsTable, item 60) inserts item 60 into bucket Ex: 10 Hashinsert(vals Table, item 83) inserts item 83 into bucket Hashinsert(vals Table, item 87) inserts item 87 into bucket

valsTable: o 50 1 51 2 3 4 5 6 7 8 9 st 67 Empty-since-start Empty-after-removal Occupied Hash table valsTable uses linear probing and a hash function of key % 10. HashInsert(valsTable, item 60) inserts item 60 into bucket Ex: 10 Hashinsert(vals Table, item 83) inserts item 83 into bucket Hashinsert(vals Table, item 87) inserts item 87 into bucket

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Trace Linear Probing with My Data A The hash table is size 7 and uses open addressing and linear probing. The hash function is hashCode(phone number) = last four digits % table size 555-1432 VoterA 555-6135 VoterB 555-2747 VoterC 555-6118 VoterD 555-5733 VoterE 555-4722 VoterF 555-7523 VoterG Show the hashCode of each Voter. Show the table after inserting the above voters in the listed order. Assume you want to retrieve each voter. How many seeks does it take to find each voter? How many seeks would it take to know that 555-5357 VoterH is not in the table? What does the table look like if you remove VoterF? Now how many seeks does it take to know that 555-5357 VoterH is not in the table? How many seeks does it take to retrieve voter G?
vals Table: o 1 2 3 4 5 6 7 8 9 10 30 21 Empty-since-start Empty-after-removal Occupied Hash table valsTable uses double probing with the hash functions hash1(key): key % 11 hash2(key): 5-key % 5 and a table size of 11. HashInsert(vals Table, item 63) inserts item 63 into bucket Ex: 10 HashInsert(vals Table, item 62) inserts item 62 into bucket HashInsert(vals Table, item 32) inserts item 32 into bucket
valsTable: o Empty-since-start 1 Empty-after-removal Occupied Hash table valsTable uses double probing with the hash functions hash1(key): key % 11 hash2(key): 5 - key % 5 and a table size of 11. 15 5 27 6. 7 HashInsert(valsTable, item 70) inserts item 70 into bucket Ex: 10 8 9 Hashlnsert(valsTable, item 62) inserts item 62 into bucket 10 Hashlnsert(valsTable, item 59) inserts item 59 into bucket 2. 3.
When there is no collision, the execution time to find an element in a hash table is O(1). Question 7 options: True Fals
write solution step by step A bloom filter with two hash functions h1(x)=x%7 and h2(x)=(3x+2) % 7 accommodates the element 19 and 16 in it. Now the user checks with the query for the elements {15,31}. Justify the answer for the query write solution step by step
3. Double hashing is one of the methods to resolve collision. Write a function to implement this method. The equations used in this method are given below. Note: implement everything within the double hash function. P = (P + INCREMENT(Key)) mod TABLE_SIZE INCREMENT(Key) = 1 + (Key mod INCR)
The hash table array has capacity of 10. Capacity is the number of slots present in the array that is used to build the hashtable. The hash function returns the absolute value of the key mod the capacity of the hash table. a) Insert these keys in the hash table: 3,23,11,21,1,7,77,8 where the hash table uses quadratic probing to resolve collisions. b) Search and Delete 3 and 11 from the table. Be careful about changing the status of the table slot to “deleted” after deleting each item. c)Search 23 and 21 from the table and print their position.
When a collision occurs during the insertion of an entry to a hash table, _finds the next available location sequentially. linear probing hashing linking O quadratic probing
Draw the contents of the hash table given the following conditions: • The size of the hash table is 18. • Linear Probing is used to resolve collisions. • The hash function H(k) should be calculated in the following way where k is the element to be hashed: R(k) = k mod (summation of last two digits of your student id) If R(k)<10 H(k)=R(k)+8 else H(k)=R(k)-2 What values will be in the hash table after the following sequence of insertions? 35, 18, 8, 13, 11, 49, 16, 27 [Note: Draw the values using a hash table and show your work for partial credit.]
Jump to level 1 An empty hash table hashTable has 15 buckets and a hash function of key % 15. The following operations are performed in order. Select which operations cause a collision. HashInsert(hashTable, 33) HashInsert(hash Table, 3) HashInsert(hash Table, 44) HashInsert(hash Table, 18) HashInsert(hash Table, 48)
Insert the following data into a hash table implemented using linear openaddressing. Assume that the buckets have three slots each. Make use of the hashfunction h(X) = X mod 9.{17, 09, 34, 56, 11, 71, 86, 55, 22, 10, 4, 39, 49, 52, 82, 13, 40, 31, 35, 28, 44}
Jump to level 1 valsTable: o 1 2 3 4 5 6 76 7 8 98 6 Empty-since-start Empty-after-removal Occupied Hash table vals Table uses quadratic probing, a hash function of key % 10, c1 = 1, and c2 = 1. HashInsert(valsTable, item 88) inserts item 88 into bucket Ex: 10 HashInsert(valsTable, item 25) inserts item 25 into bucket HashInsert(valsTable, item 76) inserts item 76 into bucket