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Vcc = 12 V R2 Rc 300 k2 22 k2 R3 R1 RỊ vo 1 k2 Rc R3, 1 k2 100 k2 Rg = R||R2 22 k2 R1. 104 k2 100 kQ RE C3→0 Signal 160 k2 13 k. source (b) (a) R1 R; Rg Rc Ra Ube RB Ube RL Vo T&mUbe 8m Ube RL (d) Figure 13.18 (a) Common-emitter amplifier circuit employing a bipolar transistor; (b) ac equivalent circuit for the common- emitter amplifier in part (a); the common-emitter connection should now be evident; (c) ac equivalent circuit with the bipolar transistor replaced by its small-signal model; (d) final equivalent circuit for ac analysis of the common-emitter amplifier.

Vcc = 12 V R2 Rc 300 k2 22 k2 R3 R1 RỊ vo 1 k2 Rc R3, 1 k2 100 k2 Rg = R||R2 22 k2 R1. 104 k2 100 kQ RE C3→0 Signal 160 k2 13 k. source (b) (a) R1 R; Rg Rc Ra Ube RB Ube RL Vo T&mUbe 8m Ube RL (d) Figure 13.18 (a) Common-emitter amplifier circuit employing a bipolar transistor; (b) ac equivalent circuit for the common- emitter amplifier in part (a); the common-emitter connection should now be evident; (c) ac equivalent circuit with the bipolar transistor replaced by its small-signal model; (d) final equivalent circuit for ac analysis of the common-emitter amplifier.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Verify the bias point values used as shown by directly calculating the Q-point.

Vcc = 12 V R2 Rc 300 k2 22 k2 R3 R1 RỊ vo 1 k2 Rc R3, 1 k2 100 k2 Rg = R||R2 22 k2 R1. 104 k2 100 kQ RE C3→0 Signal 160 k2 13 k. source (b) (a) R1 R; Rg Rc Ra Ube RB Ube RL Vo T&mUbe 8m Ube RL (d) Figure 13.18 (a) Common-emitter amplifier circuit employing a bipolar transistor; (b) ac equivalent circuit for the common- emitter amplifier in part (a); the common-emitter connection should now be evident; (c) ac equivalent circuit with the bipolar transistor replaced by its small-signal model; (d) final equivalent circuit for ac analysis of the common-emitter amplifier.
Transcribed Image Text:Vcc = 12 V R2 Rc 300 k2 22 k2 R3 R1 RỊ vo 1 k2 Rc R3, 1 k2 100 k2 Rg = R||R2 22 k2 R1. 104 k2 100 kQ RE C3→0 Signal 160 k2 13 k. source (b) (a) R1 R; Rg Rc Ra Ube RB Ube RL Vo T&mUbe 8m Ube RL (d) Figure 13.18 (a) Common-emitter amplifier circuit employing a bipolar transistor; (b) ac equivalent circuit for the common- emitter amplifier in part (a); the common-emitter connection should now be evident; (c) ac equivalent circuit with the bipolar transistor replaced by its small-signal model; (d) final equivalent circuit for ac analysis of the common-emitter amplifier.
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