3 Kieait + Kąteait, if a, = a2.+ VLProblem 1: Appearing to the right is our familiarRLC series circuit. The voltage source, va, is a con-stant voltage, and because of the capacitor in the loopthe particular (steady-state) solution for i1 is zero. Ap-pearing below is the solution for the current throughthe circuit. Note: This is an easy look-up-the-formula-and-plug-in-the-numbers problem. Don't worry, it getsele+Va+C=v,better.R-part (t) = 0(Kieit + K2ezt,if a1 7 a2;-comp(t)Kjeªit + K2teªit, if a1 = a2.i1(t) = i1-comp(t) + i1–part (t)where2R+2L1RR1LCaj =anda2 =2L2L2LLC(a) In design X the supply is va = 5 V, and the component values are R = 100 k2, L = 20 mH, andC = 30 µF.What is the resonant frequency, wo, of design X?Is design X O underdamped, O critically damped, orO overdamped?Show yourwork.(b) Starting with design X, choose values of R that will result in each damping case. One of thosevalues will be the R100 kN from design X.For an underdamped circuit change R to:For a critically damped circuit change R to:For an overdamped circuit change R to:

A steady-state is a state or condition of a system or process (such as one of an atom's energy…

+ VL Problem 1: Appearing to the right is our familiar RLC series circuit. The voltage source, va, is a con- stant voltage, and because of the capacitor in the loop the particular (steady-state) solution for i1 is zero. Ap- pearing below is the solution for the current through the circuit. Note: This is an easy look-up-the-formula- and-plug-in-the-numbers problem. Don't worry, it gets better. + Va + R i1-part (t) = 0 S Kjeªit + K2eª2t, |Kjeªit + K2teª1t, if a1 = a2. i1(t) = i1-comp(t) +ij-part (t) if a1 # a2; i1 !-comp(t) where R R + 2L'V(2L 1 R R 1 aj = - and a2 = LC 2L 2L LC (a) In design X the supply is va = 5 V, and the component values are R= 100 kN, L = 20 mH, and C= 30 μF. What is the resonant frequency, wo, of design X? Is design X () underdamped, O critically damped, or O overdamped? Show your work. (b) Starting with design X, choose values of R that will result in each damping case. One of those values will be the R= 100 kN from design X. For an underdamped circuit change R to: For a critically damped circuit change R to: For an overdamped circuit change R to:

+ VL Problem 1: Appearing to the right is our familiar RLC series circuit. The voltage source, va, is a con- stant voltage, and because of the capacitor in the loop the particular (steady-state) solution for i1 is zero. Ap- pearing below is the solution for the current through the circuit. Note: This is an easy look-up-the-formula- and-plug-in-the-numbers problem. Don't worry, it gets better. + Va + R i1-part (t) = 0 S Kjeªit + K2eª2t, |Kjeªit + K2teª1t, if a1 = a2. i1(t) = i1-comp(t) +ij-part (t) if a1 # a2; i1 !-comp(t) where R R + 2L'V(2L 1 R R 1 aj = - and a2 = LC 2L 2L LC (a) In design X the supply is va = 5 V, and the component values are R= 100 kN, L = 20 mH, and C= 30 μF. What is the resonant frequency, wo, of design X? Is design X () underdamped, O critically damped, or O overdamped? Show your work. (b) Starting with design X, choose values of R that will result in each damping case. One of those values will be the R= 100 kN from design X. For an underdamped circuit change R to: For a critically damped circuit change R to: For an overdamped circuit change R to:

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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