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Hello, can you help me with this physics exercise? I have a few questions that I need to be clear, please kindly explain to me! Thanks a lot!!!!
Q1: why vf is not 0?
Q2: why we can not use v=v0=gt to find a?
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- dN MV² F(V)dV =! N = 47 v²exp(- 2RT -)dv 2TRT Find the Vm value by considering the following curve 20 x 10- 298 10x 10 5x 10 Vm Vm 00st big diop of ladie Ru faumed 220om 1000 deehlele of wali The radius of e deoplet aell be @JOR 6 O oo t00grdeperdent w. of a partile of a The nowingm 4x 4 ip polential maRe mou le a Condat expE ちく $ind the % * the lan plem energ of
- Prove that Vav= 0.92 VrmsMhul0.mehil...w = FjAc = F .Aë , W = m(v;)* - m(u,)* , v 1 zm(us)* - m(v,)* , W = Problem 1: (a) à = 3â – 2ŷ, B = 4â& – 5ŷ. à ·B =? Answer: 22 (b) à = -2â + 4ŷ, B = 3âu – lŷ. Ā·B =? Answer: –10 (c) à = 5â – 3ŷ, B = -3â – 5ŷ. ÷B =? Answer: 0 1 | F,dx , W = F. dř , F, dU W = -AU dx d = 4m F = 20 N 0 = 30° m = 4 kg Hk = 0.5) m = 2 kg F = 40 N Hk = 0.2 Ө — 30° Problem 2: In the figure above on the left we have a force F = 20 N pulling a box to the right at an angle 0 = 30° above the horizontal. The box has a mass m = 2 kg, the coefficient of kinetic firction between the box and the ground is uk = 0.2, and the block moves a distance d = 4 m to the right. (a) What is the work done by the force F? Answer: 69.3 J (b) What is the normal force from the ground? Use g = 10 m/sec² Answer: 10 N (c) What is the work done by the kinetic friction force? Answer: -8 J (d) What is Wnet, the net work done on the box? Answer: 61.3 J (e) The box has an initial speed of 4 m/sec. What is the speed of the box after it has…
- Growth of yeast cells In a controlled laboratory experiment, yeast cells are grown in an automated cell culture system that counts the number P of cells present at hourly intervals. The num- ber after t hours is shown in the accompanying figure. 250 200 150 100 50 0 1 2 3 4 5 6 7 a. Explain what is meant by the derivative P'(5). What are its units? b. Which is larger, P'(2) or P'(3)? Give a reason for your answer. c. The quadratic curve capturing the trend of the data points (see Section 1.4) is given by P(t) = 6.10r2 – 9.28t + 16.43. Find the instantaneous rate of growth when t = 5 hours.27. S Review. From the set of equations p = 3q pr = qs involving the unknowns p, q, r, s, and t, find the value of the ratio of t to r.b): The patcutal 0.21 partile a abag the X-aris is Ulx)=822x" is Where Joules meters.2Iher is Dill be and the at Xelom, in in That acelention,