How many protons are needed to have a charge of 15 uc?8.31 x 10^13 protons5.85 x 10^13 protonsO 4.46 x 10^13 protonsO 3.16 x 10^13 protonsO 9.38 x 10^13 protons56

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w many protons are needed to have a charge of 15 uC? 8.31 x 10^13 protons 5.85 x 10^13 protons 4.46 x 10^13 protons 3.16 x 10^13 protons O 9.38 x 10^13 protons

Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter19: Electric Forces And Electric Fields

Section: Chapter Questions

Problem 6OQ

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A proton is located at the origin, and a second proton is located on the x-axis at x = 6.00 fm (1 fm = 10-15 m). (a) Calculate the electric potential energy associated with this configuration. (b) An alpha particle (charge = 2e, mass = 6.64 1027 kg) is now placed at (x, y) = (3.00, 3.00) fm. Calculate the electric potential energy associated with this configuration. (c) Starting with the three-particle system, find the change in electric potential energy if the alpha particle is allowed to escape to infinity while the two protons remain fixed in place. (Throughout, neglect any radiation effects.) (d) Use conservation of energy to calculate the speed of the alpha particle at infinity. (e) If the two protons are released from rest and the alpha panicle remains fixed, calculate the speed of the protons at infinity.
An electron is to be accelerated in a uniform electric field having a strength of 2.00106 V/m. (a) What energy in keV is given to the electron if it is accelerated through 0.400 m? (b) Over what distance would it have to be accelerated to increase its energy by 50.0 GeV?
(a) Find the potential difference VB required to stop an electron (called a slopping potential) moving with an initial speed of 2.85 107 m/s. (b) Would a proton traveling at the same speed require a greater or lesser magnitude potential difference? Explain. (c) Find a symbolic expression for the ratio of the proton stopping potential and the electron stopping potential, Vp/Ve. The answer should be in terms of the proton mass mp and electron mass me.
You are working on a research project in which you must control the direction of travel of electrons using deflection plates. You have devised the apparatus shown in Figure P22.28. The plates are of length = 0.500 m and are separated by a distance d = 3.00 cm. Electrons are fired at vi = 5.00 106 m/s into a uniform electric field from the left edge of the lower, positive plate, aimed directly at the right edge of the upper, negative plate. Therefore, if there is no electric field between the plates, the electrons will follow the broken line in the figure. With an electric field existing between the plates, the electrons will follow a curved path, bending downward. You need to determine (a) the range of angles over which the electron can leave the apparatus and (b) the electric field required to give the maximum possible deviation angle. Figure P22.28
A proton and an alpha particle (charge = 2e, mass = 6.64 1027 kg) are initially at rest, separated by 4.00 1015 m. (a) If they are both released simultaneously, explain why you cant find their velocities at infinity using only conservation of energy. (b) What other conservation law can be applied in this case? (c) Find the speeds of the proton and alpha particle, respectively, at infinity.
Lightning can be studied with a Van de Graaff generator, which consists of a spherical dome on which charge is continuously deposited by a moving belt. Charge can be added until the electric field at the surface of the dome becomes equal to the dielectric strength of air. Any more charge leaks off in sparks as shown in Figure P25.52. Assume the dome has a diameter of 30.0 cm and is surrounded by dry air with a "breakdown" electric field of 3.00 106 V/m. (a) What is the maximum potential of the dome? (b) What is the maximum charge on the dome?
(a) Find the potential difference VB required to stop an electron (called a slopping potential) moving with an initial speed of 2.85 107 m/s. (b) Would a proton traveling at the same speed require a greater or lesser magnitude potential difference? Explain. (c) Find a symbolic expression for the ratio of the proton stopping potential and the electron stopping potential, Vp/Ve. The answer should be in terms of the proton mass mp and electron mass me.
What would be the initial acceleration of the electron with distance of 4.52 cm to the left of an 8.15 mC negative charge?a) 7.28 x 10^19 m/s^2c) 2.70 x 10^19 m/s^2b) 6.31 x10^21 m/s^2d) 3.59 x 10^15 m/s^2
Determine the distance between a proton and electron if the force between them is 28 pN. 2.87 nm 2.78 pm 2.76 km 2.67 mm
you have been given some info, use it to solve the questions highlighted in yellow. - an alpha particle has charge 2e and mass 6.64x10^(-27). - The alpa particle is shot aimed at a gold nucleus which is stationary. The gold nucleus has a charge of 79e. - Then the gold nucleus and the alpha particle are 10cm appart from eachother, the alpha particle moves at 1000m/s. a. What is the speed of the alpha particle when it is 1.00mm away from the gold nucleus? b. What is the closest distance the alpha particle can go reletive to the gold nucleus before the alpha particle rebounds ?
A point charge, q=+8.00pC, and mass, m=2.00x10^-14 kg starts from rest on a planar, infinite sheet of charge with uniform density, σ=+3.00pC. When the point charge rises 1.00 cm above the infinite sheet, how fast will it be moving? a. 16 m/s b. 22 m/s c. 350 m/s d. 43 x 105 m/s e. 87 x 106 m/s
An alpha particle (charge +3.20 x 10-19C, mass 6.64 x 10-27kg) is initially 5.2 cm away from a fixed gold nucleus (charge +1.26 x 10-17C, mass 3.29 x 10-25kg) and moving toward the nucleus with a speed of 8.1 x 105m/s. How close to the nucleus does the alpha particle get? (Note: The nucleus diameter is approximately 10-14m and the and alpha particle’s is 10-15m.)