Water (1) and methanol (2) are mixed to form a non-ideal binary mixture solution at constant T and P, and the molar volumes of the resultant mixture (V) are measured and tabulated as follows: Given that: AV mix AV mix where =X₁ d(AVmix) dx₁ d(AV mix) dx₁ -X₂ X1 0 0.116 0.222 0.284 0.373 0.419 0.527 0.612 0.722 0.851 0.949 1 +(V₂ -V₂) + +(V₁-V₁) V (cm³/mol) 40.72 37.70 35.02 33.50 31.36 30.28 27.79 25.91 23.58 21.00 19.08 18.07 AV mix = molar volume of mixing V₁, V₂ = partial molar volume of species 1 and 2 respectively V₁, V₂ = molar volume of pure species 1 and 2 respectively X₁, X2 = mole fraction of species 1 and 2 respectively Plot AV mix VS. X1, and determine graphically the value of V₁ and V₂ at x1 = 0.45.

Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Water (1) and methanol (2) are mixed to form a non-ideal binary mixture solution at constant T
and P, and the molar volumes of the resultant mixture (V) are measured and tabulated as follows:
Given that:
AV mix
AV
=X₁1
X1
0
0.116
0.222
0.284
0.373
0.419
0.527
d(AV mix)+(√₂-V₂)
dx₁
d(AV mix)+(V₁-V₁)
dx₁
mix = -X₂
0.612
0.722
0.851
0.949
1
V (cm³/mol)
40.72
37.70
35.02
33.50
31.36
30.28
27.79
25.91
23.58
21.00
19.08
18.07
where
AV
mix molar volume of mixing
V₁, V₂
= partial molar volume of species 1 and 2 respectively
V₁, V₂
= molar volume of pure species 1 and 2 respectively
X₁, X2
= mole fraction of species 1 and 2 respectively
Plot AV mix VS. X1, and determine graphically the value of V₁ and V₂ at x1 = 0.45.
Transcribed Image Text:Water (1) and methanol (2) are mixed to form a non-ideal binary mixture solution at constant T and P, and the molar volumes of the resultant mixture (V) are measured and tabulated as follows: Given that: AV mix AV =X₁1 X1 0 0.116 0.222 0.284 0.373 0.419 0.527 d(AV mix)+(√₂-V₂) dx₁ d(AV mix)+(V₁-V₁) dx₁ mix = -X₂ 0.612 0.722 0.851 0.949 1 V (cm³/mol) 40.72 37.70 35.02 33.50 31.36 30.28 27.79 25.91 23.58 21.00 19.08 18.07 where AV mix molar volume of mixing V₁, V₂ = partial molar volume of species 1 and 2 respectively V₁, V₂ = molar volume of pure species 1 and 2 respectively X₁, X2 = mole fraction of species 1 and 2 respectively Plot AV mix VS. X1, and determine graphically the value of V₁ and V₂ at x1 = 0.45.
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