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We have to determine the equations of the tangents drawn from the point P(5,-3) to the ellipse x² + 4y² + 2x +2x-12y + 6 = -(1) Differentiating with respect to x 2x+8ydy + 2- x² + 4y² + 2x-12y+6=0 dy ds dy (8y- 12) = (2x+2) ds or dy ds = = - 12d4 = 0 -(x+1) 4y-6 x+1 2(3-2y) - x+1 2(3-2y) or. 2(y + 3) (3-2y) = (x + 1)(x - 5) or, The equations of tangents drawn from the point are. P (5,-3) to the ellipse (1) y+3= (x-5) we 2 get. x-5xx-5 2(Зу+9-2у2-бу) 2. -18²-6y +18 = x²=4x-5 x² + 4y²-4x+6y-23 -23 = 0

We have to determine the equations of the tangents drawn from the point P(5,-3) to the ellipse x² + 4y² + 2x +2x-12y + 6 = -(1) Differentiating with respect to x 2x+8ydy + 2- x² + 4y² + 2x-12y+6=0 dy ds dy (8y- 12) = (2x+2) ds or dy ds = = - 12d4 = 0 -(x+1) 4y-6 x+1 2(3-2y) - x+1 2(3-2y) or. 2(y + 3) (3-2y) = (x + 1)(x - 5) or, The equations of tangents drawn from the point are. P (5,-3) to the ellipse (1) y+3= (x-5) we 2 get. x-5xx-5 2(Зу+9-2у2-бу) 2. -18²-6y +18 = x²=4x-5 x² + 4y²-4x+6y-23 -23 = 0

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.2: Ellipses
Problem 28E
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We have to determine the equations of the tangents drawn from the point P(5,-3) to the ellipse 0. - (1) x²+4y² + 2x-12y+6=0 Differentiating with respect to x 2x+ 8ydy + +2-12d4 I or, or. or. 2 x²³²+ 4y² + 2x-12y+6=0 dx dy (8y-12) = - (2x+2) ds dy dx or dy ds or. = = (x+1) 4y-6 The equations of tangents drawn from the point P (5,-3) to the ellipse (1) are. y+3=__x+1 (x-5) x+1 2(3-2y) 2(3-2y) 2(y + 3) (3-2y) = (x + 1)(x - 5) ・get. we 2 (3y+9-2y²-6y) = x²-5x²+x-5 2 -18² -6y + 18 = x ²³²-1x-5 x² + 4y²-4x+6y-23 = 0
Transcribed Image Text:We have to determine the equations of the tangents drawn from the point P(5,-3) to the ellipse 0. - (1) x²+4y² + 2x-12y+6=0 Differentiating with respect to x 2x+ 8ydy + +2-12d4 I or, or. or. 2 x²³²+ 4y² + 2x-12y+6=0 dx dy (8y-12) = - (2x+2) ds dy dx or dy ds or. = = (x+1) 4y-6 The equations of tangents drawn from the point P (5,-3) to the ellipse (1) are. y+3=__x+1 (x-5) x+1 2(3-2y) 2(3-2y) 2(y + 3) (3-2y) = (x + 1)(x - 5) ・get. we 2 (3y+9-2y²-6y) = x²-5x²+x-5 2 -18² -6y + 18 = x ²³²-1x-5 x² + 4y²-4x+6y-23 = 0
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