What does mystryMethod void mystryMethod (Node n, int vall, int if (n.data = vall){ Node node = new Node (val2); %3D node.next = n.next; n.next = node; return; } m ruMe+hed . 11
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- using namespace std; class SinglyLinkedListNode { // INSERT YOUR CODE HERE }; class SinglyLinkedList { public: SinglyLinkedListNode *head; SinglyLinkedListNode *tail; SinglyLinkedList() { this->head = nullptr; this->tail = nullptr; } voidinsert_node(intnode_data) { // INSERT YOUR CODE HERE } }; void free_singly_linked_list(SinglyLinkedListNode* node) { // INSERT YOUR CODE HERE } // Complete the has_cycle function below. /* * For your reference: * * SinglyLinkedListNode { * int data; * SinglyLinkedListNode* next; * }; * */ bool has_cycle(SinglyLinkedListNode* head) { SinglyLinkedListNode* temp = head; bool isCycle = false; while (temp != nullptr) { // INSERT YOUR CODE HERE } } int main() { // INSERT YOUR CODE HERE TO TEST YOUR CODE return0; }Write a code that will print the deleted number class LinkedList { static Node head; static class Node { int data; Node next; Node(int d) { data = d; next = null; } } void duplicateremove() { Node ptr1 = null, ptr2 = null, dup = null; ptr1 = head; while (ptr1 != null && ptr1.next != null) { ptr2 = ptr1; while (ptr2.next != null) { if (ptr1.data == ptr2.next.data) { ptr2.next = ptr2.next.next; System.gc(); } else { ptr2 = ptr2.next; } } ptr1 = ptr1.next; } } void printList(Node node) { while (node != null) { System.out.print(node.data + " "); node = node.next; } } public static void main(String[] args) { LinkedList list = new LinkedList();…Consider the following function:int mystery(NodeInt32* node){int counter = 0; while (node != NULL) {counter++;node = node->next; } return counter;}
- What does this part of code do? void addRecord(Node *& head, Node *& tail, string name, double balance){ Node *newNode = new Node; newNode->name = name; newNode->balance = balance; newNode->next = NULL; newNode->prev = NULL; // If list is empty, make newNode the first node if(head == NULL){ head = newNode; tail = newNode; } else{ Node *temp = head; // Loop through list until temp->next is NULL while(temp->next != NULL){ temp = temp->next; } temp->next = newNode; newNode->prev = temp; tail = newNode; }} /*//give the output of the following program and draw the link list. struct node{ int info; struct node *link;};typedef struct node *nodePTR;void insort(nodePTR*,struct Info);nodePTR getnode();int main(void){nodePTR p=NULL,head=NULL,save;inti; for(i=0;i<3;i++){ insort (&head,i+5);}save=head;do{ printf("%d",save->info); save=save->link;}while(save!=NULL); return0;}nodePTR getnode(){nodePTR q;q=(nodePTR)malloc(sizeof(struct node));return q;}void insort(NODEPTR *head , int x){ NODEPTR p,q,r; q=NULL; for(p=*head; p!=NULL &&x>p->info; p=p->link) q=p; if(q=NULL) { p=getnode(); p->info=x; p->link=head; head=p; }else{ r=getnode(); q->link=r; r->info=x; r->link=p; }}//main.cpp #include "linkedListType.h"int main(){Node* head = NULL;orderedLinkedList oll = orderedLinkedList(head); oll.insert(40);oll.insert(100);oll.insert(50); oll.printList(); oll.insert(50);oll.printList(); return 0;} //linkedListType.h #include <stdio.h>#include <iostream>using namespace std; class Node{public:int data;Node* next;}; class orderedLinkedList {Node* head; public:orderedLinkedList(Node* h) {head = h;} void insert(int new_data){Node* head_ref = head; while (head_ref != NULL && (head_ref->next != NULL) && (head_ref->next)->data < new_data){cout << head_ref->data << "\n";head_ref = head_ref->next;} if (head_ref != NULL && (head_ref->next != NULL) && (head_ref->next)->data == new_data){cout << "ERROR: Item to be inserted is already in the list\n";return;} /* Insert new node */Node* new_node = new Node();new_node->data = new_data;if (head_ref != NULL) {new_node->next =…
- void traverse (Node node){ if (node.left!=null){ traverse (node.left); System.out.print (node.data+" ->"); } if(node.right!=null){ System.out.print (node.data+" ->"); traverse (node.right); } } Write the output that will be obtained when this traverse() method is called with the root of the tree given below. 8 4 12 2 6 10 14 1 3 5 7) 9 )( 11 13 15Assume the following method is within the SingleLinkedList class. What does it do? public void unknownMethod() { Node pt = tail; E temp; while (pt != null && pt.prev != null) { temp = pt.data; pt.data = pt.prev.data; pt.prev.data= temp; pt = pt.prev; } A) Exchanges the data of the first node with the data of the last node. Makes the data of the last node to move to become the data of the first node. Exchanges the data of the last two nodes. D Makes the data of the second node to move to be the data of the last node.bool DelOddCopEven(Node* headPtr);
- void listEmployees (void) { for (int i=0; i 10000. Make a guess about why the comparison function takes 2 struct Employee parameters (as opposed to struct Employee *) **Given the following definition for a LinkedList: // LinkedList.h class LinkedList { public: LinkedList(); // TODO: Implement me void printEveryOther() const; private: struct Node { int data; Node* next; }; Node * head; }; // LinkedList.cpp #include "LinkedList.h" LinkedList::LinkedList() { head = nullptr; } Implement the function printEveryOther, which prints every other data value (i.e. those at the odd indices assuming 0-based indexing).typedef struct node{int data;struct node *left,*right;}BST;The node structure of BST is shown above. Please design an efficient algorithm to return the maximum keyword value in BST. Completion function: int findmax (BST *T)