What happens when the loop encloses no current?What happens when the loop encloses both positive (out of the screen) and negative (into the screen) currentThe four sides of the path contribute different amounts to the total integral. Under which circumstances will the contribution from a side be zero?The magnetic field within a solenoid is uniform. By playing around with this simulation, can you explain why that must be the case? p00000000000odo000obo00000000000000000003B = 18.85 mT00001 mmPath 1:Path 2:[8. di = 0 mT - mm[6 . ds = 5.84 mT mmTurns/Length :Path 3:Path 4:n = 5 mm-B. ds = 25.32 mT - mmds = -10.05 mT · mmCurrent :Complete Path :lenc = 16.81 A|= 3 AB - ds = 21.12 mT - mmHo lene = 21.12 mT. mm

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Answered: What happens when the loop encloses no…

College Physics

1st Edition

ISBN:9781938168000

Author:Paul Peter Urone, Roger Hinrichs

Publisher:Paul Peter Urone, Roger Hinrichs

Chapter24: Electromagnetic Waves

Section: Chapter Questions

Problem 2PE: Show that, when SI units for 0 and 0 are entered, the units given by the right-hand side of the...

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What happens when the loop encloses no current?
What happens when the loop encloses both positive (out of the screen) and negative (into the screen) current
The four sides of the path contribute different amounts to the total integral. Under which circumstances will the contribution from a side be zero?
The magnetic field within a solenoid is uniform. By playing around with this simulation, can you explain why that must be the case?

p00000000000odo000obo0000000000000000000
3
B = 18.85 mT
0000
1 mm
Path 1:
Path 2:
[8. di = 0 mT - mm
[6 . ds = 5.84 mT mm
Turns/Length :
Path 3:
Path 4:
n = 5 mm-
B. ds = 25.32 mT - mm
ds = -10.05 mT · mm
Current :
Complete Path :
lenc = 16.81 A
|= 3 A
B - ds = 21.12 mT - mm
Ho lene = 21.12 mT. mm

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