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- A carbon nanotube is a nanometer-scale cylindrical tube composed of carbon atoms. One of its interesting properties is a very large Youngs modulus, measured to be more than 1.000 1012 N/m2. A tensile stress of 5.3 1010 N/m2 is exerted on a particular nanotube with a Youngs modulus measured at 2.130 1012 N/m2. Assuming the nanotube obeys Hookes law, by what percentage does the atomic spacing increase?In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A= i-hat + j-hat + k-hat and an adjacent C-H bond is at the direction B= i-hat - j-hat - k-hat results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 1.09i + 1.06j + 1.02k B = 1.01i + -0.89j + -1.02k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A= i-hat + j-hat + k-hat and an adjacent C-H bond is at the direction B= i-hat - j-hat - k-hat results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.96i + 0.87j + 0.8k B = 0.94i + -0.98j + -1.07k What is the angle (in degrees) between the bonds based on this new data?
- In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of and an adjacent C-H bond is at the direction . results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.84i + 0.96j + 0.9k B = 0.87i + -0.94j + -1.07k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of and an adjacent C-H bond is at the direction . results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.95i + 0.87j + 0.99k B = 1.06i + -1.08j + -0.93k What is the angle (in degrees) between the bonds based on this new data?In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of and an adjacent C-H bond is at the direction . results to an angular bond of approximately 109o for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.93i + 0.91j + 1.09k B = 1.02i + -0.99j + -1.08k
- In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A =î +Î+k and an adjacent C-H bond is at the direction B=1-7-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.99i + 0.98j + 0.97k B = 0.95i + -0.94j + -1.01k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A = î +ĵ +k and an adjacent C-H bond is at the direction B=î-Î- R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.8i + 0.85j + 1.05k B = 1.05i + -0.87j + -0.96k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=î+î +k and an adjacent C-H bond is at the direction B=î-ĵ-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 1.02i + 0.87j + 0.96k B = 0.94i + -1.09j + -0.92k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.
- In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction ofIn the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A= î +Î+k and an adjacent C-H bond is at the direction B=î-Î-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A = 0.93i + 0.91j + 1.09k B = 1.02i + -0.99j + -1.08k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.In the methane molecule, CH4, each hydrogen atom is at the corner of a regular tetrahedron with the carbon atom at the center. If one of the C-H is in the direction of A=î + Î +R and an adjacent C-H bond is at the direction B=î-1-R. results to an angular bond of approximately 109° for a static frozen molecule. However, the molecule we can encounter everyday continuously vibrates and interact with the surrounding causing its bond vector to vary slightly. According to a new spectroscopy analysis, the adjacent bond vectors was found to be A= 1.01i + 1.07j + 1.09k B = 0.92i + -1.07j + -1.04k What is the angle (in degrees) between the bonds based on this new data? Note: Only 1% of error is permitted for the correct answer.