What is the distance from the sun to venus written in the scientific notation Please make sure to include your units s) (4-1)2t)45ategory 2)(d) What is the distance from the sun to Venus written in scientific notation?"lease make sure to include your units(Ctrl) ►tegory 3)A few quick reminders:You are only selecting 1 choice per category. Additional credit will not be awn alternatived as

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What is the distance from the sun to venus written in the scientific notation Please make sure to include your units

Horizons: Exploring the Universe (MindTap Course List)

14th Edition

ISBN:9781305960961

Author:Michael A. Seeds, Dana Backman

Publisher:Michael A. Seeds, Dana Backman

Chapter1: Here And Now

Section: Chapter Questions

Problem 1P: The diameter of Earth across the equator is 7928 miles. If a mile equals 1.609 km. what is Earths...

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You decide to go on an interstellar mission to explore some of the newly discovered extrasolar planets orbiting the star ROTOR. Your spacecraft arrives in the new system, in which there are five planets. ROTOR is identical to the Sun (in terms of its size, mass, age and composition). From your observations of these planets, you collect the following data: Density Average Distance from star (AU] Planet Mass Radius Albedo Temp. [C] Surf. Press. MOI Rotation [Earth = 1] (Earth = 1] [g/cm³] [Atm.] Period (Hours] Factor SIEVER EUGENIA 4.0 0.001 2.0 0.1 5.0 1.0 0.3 20 0.8 N/A 3.0 0.2 N/A 0.3 0.4 0.35 20 10 500 1000 5.0 4.0 0.5 0.8 0.4 0.7 -50 MARLENE CRILE 1.0 1.0 3.0 8.0 1,5 0.0 0.50 0.50 0.25 150 0.4 JANUS 100 12 0.1 10 -80 0.2 200 Figure 1: А Rotor 850 890 900 Wavelength (nm) A Sun В C 860 900 910 Wavelength (nm) 2414 a as
1 "g'on MARS= O038 "7'aNEARTH. RADIUS OR MARS = 3400kM USING VALUES PROVIOAO pOR G ANO RAOCEAATA) Mmam FINO MASS OA MARS
(a) How many seconds are there in a year? (b) If one micrometeorite (a sphere with a diameter on the order of 106 m) struck each square meter of the Moon each second, estimate the number of years it would take to cover the Moon with micrometeorites to a depth of one meter. (Hint: Consider a cubic box, 1 m on aside, on the Moon, and find how long it would take to fill the box.)
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When the Earth passes directly between the Sun and Mars, the Earth and Mars are closest to each other. If Mars is 1.52 AU from the Sun and there are 1.5 x 108 km in 1 AU, how many times will the width of the U.S. (2,530 miles) fit end-to-end between Mars and Earth? Planets and Sun not drawn to scale. Mars Earth Sun Part 1 of 4 Mars is 1.52 AU from the Sun. How many times further away from the Sun is Mars than the Earth? (The distances in AU are relative to the distance between the Sun and the Earth, so however many AU a planet is away from the Sun is how many times farther it is from Sun than Earth.) 1.52✔ 1.52 times further away
4) Science fiction movies often portray asteroid belts as crowded, dense regions that require spaceships to maneuver quickly to get through them. In this problem, we will calculate the fraction of volume in an asteroid belt that is actually occupied by asteroids. a) If there are 300,000 large asteroids between 2 and 3 AU from the Sun, and each asteroid is assumed to be spherical with a radius of 100 km, determine the total volume occupied by asteroids in this region. Recall that the volume of a sphere is given by the equation V = 4TR³ /3. b) Let's assume the region in which these asteroids orbit is an annulus with an inner radius of 2 AU, an outer radius of 3 AU, and a thickness of 2Ro. Determine the volume of this region. Recall that the area of a circle is given by the equation A = TR². Here are two conversions that you'll need: 1 AU = 1.496 × 108 km and 1 Ro = 6.955 × 105 km. c) What is the ratio of the volume occupied by asteroids to the volume of the asteroid belt (i.e., the…
The average Earth-Moon distance is 3.84 X 10^5 km, while the Earth-Sun is 1.496 X 10^8 km. Since the radius of the Moon is 1.74 X 10^3 km and that of the Sun is 6.96 X 10^5 km. a) Calculate the angular radius of the Moon and the Sun, qmax, according to the following figure. D Bax R b) Calculate the solid angle of the Moon and the Sun as seen from Earth. (c) Interpret its results; Would this be enough to explain the occurrence of total solar eclipses?
expressed as length { in meters seconds squared, or . h divide out and T = VT2. The factor 2T has no units so d in the analysis. 10. The period of rotation of the Sun is 2.125 x 106 seconds. This is equivalent to 2.125 (2) ms (1) us (3) Ms (4) Ts 11. Human hair grows at the rate of 3 nanometers per second. This rate is equivalent to (1) 3 x 10-3 m/s (2) 3 x 10-6 m/s (3) 3 x 10-9 m/s (4) 3 x 10-12 m/s 12. The wavelength of red light is 7 x 10-7 meter. Express this value in nanometers. 13. If m represents mass in kg, v represents speed in m/s, and r represents radius in m, show that the force F in the formula F = in the unit kg m/s2. mv? can be expressed 14. If PE, represents the potential energy stored in a spring in kg m2/s², and x represents the change in spring length from its equilibrium position in m, what is the unit for the spring constant k in the formula RE
1. The diameter of the Sun is equal to 1.392*10^9 m, and the distance from the Sun to Saturnis equal to 9.5 AU. Suppose you want to build an exact scale model of the solar system,and you are using a volleyball with average diameter of 21 cm to represent the Sun. a) In your scale model, how far away would Saturn be from the Sun? Give your answer inmeters.b) The actual diameter of Saturn is 116,460 km. What would be Saturn’s diameter in yourscale model? Give your answer in centimeters.
DUE IN 30 MINUTES. Please answer it with GRESA Format (Given, Required, Solutions, and Answers). Please also make the solutions neatly and as detailed as possible. Thanks a lot!
The angle on the sky between Venus and the Sun is measured to be 46.3° when Venus is at greatest eastern elongation. What is the distance of Venus from the Sun, measured in AU? Choose the answer below that most closely matches your answer. Select one: а. 1.763 AU O b. 0.587 AU Ос. 0.652 AU O d. 0.846 AU Ое. 0.723 AU
A)At what altitude would a geostationary sattelite need to be above the surface of Mars? Assume the mass of Mars is 6.39 x 1023 kg, the length of a martian solar day is 24 hours 39minutes 35seconds, the length of the sidereal day is 24hours 37minutes 22seconds, and the equatorial radius is 3396 km. The answer can be calculated using Newton's verison of Kepler's third law.