What is the flatness tolerance for the surface being controlled in the drawing below? 25° 2.005 A A
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- What is the worst-case distance between the bottom surface of the slot and the bottom surface of the part in the drawing below? B 4.000-4.020 1.475 O 1.030 2.950 B 4.00 O 1.450 O 1.500 1.000-1.010 .010M ABM 2.00 AInformation such as tolerances and scale can be found in the________ of an engineering drawing.What is the worst-case distance between the bottom surface of the slot and the bottom surface of the part in the drawing below? B 4.000-4.020 O 1.475 O 1.450 O 2.950 O 1.500 O 1.030 4.00 0.010MABM 1.000-1.010 2.00 A
- On the toleranced rectangle below, what is the tolerance within which the top surface must be parallel to the bottom surface? 0.002 O .002 1.015 1.000 O There is no tolerance within which the top surface must be parallel to the bottom surface O .015Build the following part. Report the mass in pounds. Assume all dimensions are in inches. The material is Vanadium. (Located in the "Other Metals" folder in the material properties.) A = 1.72 B = 1.4 2.40 1.20 T .75 TYP 1.20 TYP .70 -1.00 TYP A A A+3.25 R.35 TYP -R.65 TYP CBORE FOR 5/16 HEX HEAD BOLT Ø.332 THRU ALL LØ813 V 235 .10- SECTION A-A 23. B B+1Draw the SECTION VIEW with the scale 1:1 on the new drawing paper using all the method on section. Dimension must be included. All dimension in mm. You are require to draw again the A-A section. Please answer this question..if answer i give u good review
- Suppose that the length of the steel bar is measured by a number of different observers and following set of 11 measurements is recorded as set A (units mm): 398, 420, 394, 416, 404, 408, 400, 420, 396, 413, 330. Next the measurements are taken using different ruler to produce measurement set B: 409, 406, 402, 407, 405, 404, 407, 404, 407, 407, 408. It can be shown that the mean values set A and B are 409 and 406 respectively. Which of the two measurement sets A and B, and the corresponding mean value, should have most confidence in? why? TextQuestion 1 a) Calculate the following slip gauges assemble to 100.115 mm. Use the increment of 1st, 2nd, 3nd & 4th to give the total assemble of 100.115mm. NB. Use the table below. Size or Range Increment No. of Pieces 1.005 1.001-1.009 1.01 1.49 0.5-9.5 10-100 0.001 0.01 49 0.5 19 10 100.5mlm 1 3 4 5 cm mm} Consider the steel ruler shown. Which of the following dimensions can be accurately measured with this ruler? C. 1.05 mm B. 1.5 mm A. 1.25 mm D. All of these dimensions can be measured accurately
- Show the tolerance zone created by each of the given tolerance specfication. Superimpose the tolerance zone on the given drawing.2. Determine the reading on the vernier scale as indicated by the arrows. 25 30 35 40 10 20 30 40 50 Reading.. .mm 3. Determine the reading at the points shown on the steel rule: A D 1/8 1/4 12 21 A. = B. = C. = D. = Page 6 cBuild the following part and report the volume in units cubed. A = 48 B = 51 R20 R10 B 30 50 2X R10 R20 Ø20 A 10 TYP DESIGN ERICS DRAWING TITLE