What is the mass in grams of magnesium chloride that can be produced from 3.47 moles of chlorine gas reacting with excess magnesium? Mg(s) + Cl₂(g) > MgCl₂(s) What is the mass in grams of NO that can be formed from 3.68 moles of NO₂ in the reaction below? 3 NO₂ (g) + H₂O (g) > 2 HNO3 (g) + NO (g) Answer in a clear, multiplication/division format with showing all work. Acording to the balanced reaction below, calculate the quantity of moles of NH3 gas that form when 4.20 mol of N2H4 liquid completely reacts: 3 N₂H4(1) > 4 NH3(g) + N₂(g)

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Chapter3: Stoichiometry
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What is the mass in grams of magnesium chloride that can be produced from 3.47 moles of chlorine gas reacting with excess magnesium? Mg(s) + Cl₂(g) -> MgCl₂(s) What is the mass in grams
of NO that can be formed from 3.68 moles of NO₂ in the reaction below? 3 NO₂ (g) + H₂O (g) -> 2 HNO3 (g) + NO (g) Answer in a clear, multiplication/division format with showing all work.
Acording to the balanced reaction below, calculate the quantity of moles of NH3 gas that form when 4.20 mol of N2H4 liquid completely reacts: 3 N₂H4(1) - > 4 NH3(g) + N₂(g)
Transcribed Image Text:What is the mass in grams of magnesium chloride that can be produced from 3.47 moles of chlorine gas reacting with excess magnesium? Mg(s) + Cl₂(g) -> MgCl₂(s) What is the mass in grams of NO that can be formed from 3.68 moles of NO₂ in the reaction below? 3 NO₂ (g) + H₂O (g) -> 2 HNO3 (g) + NO (g) Answer in a clear, multiplication/division format with showing all work. Acording to the balanced reaction below, calculate the quantity of moles of NH3 gas that form when 4.20 mol of N2H4 liquid completely reacts: 3 N₂H4(1) - > 4 NH3(g) + N₂(g)
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