What is the maximum elongation of the spring in the following example problem, if the spring is made of phosphor bronze for which G = 42 GPa and is stressed to 140 MPa. Use Eq. (3-10). Determine the maximum shearing stress and elongation in helical steel spring composed of 20turns of 20mm-diameter wire on a mean radius of 80mm when the spring is supporting a load of2kN. UseEq. (3-10) and G = 83 GPa.Given:n = 20 turnsd = 20 mmR = 80mmP = 2KNG = 83 GPaRequired:Max. shearing stress, (rmax.)Elongation, (6)Solutions:Eq. 3-10Max. T =2RM===dMax. T =16PRnd³8 =2 (80)204m-14m-4= 816(2,000) (0.080) 4x8-1T(0.020³)4x8-4= 120.6 MPa ans.+ 0.615m64PR³nGd4(64)(2000) (0,080)³ (20)(83x10^9) (0.020)^4= 98.7mm ans.+ 0.6158

Given: Spring Material = Phosphor Bronze Modulus of Rigidity G = 42 GPa = 42 x 103 MPa = 42 x 103…

Answered: What is the maximum elongation of the…

What is the maximum elongation of the spring in the following example problem, if the spring is made of phosphor bronze for which G = 42 GPa and is stressed to 140 MPa. Use Eq. (3-10).

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter2: Axially Loaded Members

Section: Chapter Questions

Problem 2.5.29P: A polyethylene tube (length L) has a cap that when installed compresses a spring (with under-formed...

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Question

What is the maximum elongation of the spring in the following example problem, if the spring is made of phosphor bronze for which G = 42 GPa and is stressed to 140 MPa. Use Eq. (3-10).

Determine the maximum shearing stress and elongation in helical steel spring composed of 20
turns of 20mm-diameter wire on a mean radius of 80mm when the spring is supporting a load of
2kN. Use
Eq. (3-10) and G = 83 GPa.
Given:
n = 20 turns
d = 20 mm
R = 80mm
P = 2KN
G = 83 GPa
Required:
Max. shearing stress, (rmax.)
Elongation, (6)
Solutions:
Eq. 3-10
Max. T =
2R
M===
d
Max. T =
16PR
nd³
8 =
2 (80)
20
4m-1
4m-4
= 8
16(2,000) (0.080) 4x8-1
T(0.020³)
4x8-4
= 120.6 MPa ans.
+ 0.615
m
64PR³n
Gd4
(64)(2000) (0,080)³ (20)
(83x10^9) (0.020)^4
= 98.7mm ans.
+ 0.615
8

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