What is the section modulusof a tube with a diameter of100mm measured from theoutside and has a thickness of20mm. Use whole number inmm^4. * Static ParametersWebFlangeThicknessSectionalAreaMoment ofElastic SectionModulusDesignationImperial(in x Ib/ft) (in)WidthThicknessWeight(Ib/ft)Ix(in4)DepthInertiawtw(in)h(in)(In?)ly(in4)Sy(in³)(in)Sx(in³)W 27 x 178 27.8 14.09W 27 x 161 27.6 14.02W 27 x 146 27.40.7251.19052.3178699055550278.80.6601.08047.4161628049745570.9140.6050.97542.9146563044341163.5W 27 x 114 27.3 10.07W 27 x 102 27.1 10.02W 27 x 94 26.9W 27 x 84 26.70.5700.93033.5114409015929931.50,5150.83030.0102362013926727.8100.4900.74527.794327012424324.89.960.4600.64024.884285010621321.2W 24 x 162 25W 24 x 146 24.7W 24 x 131 24.5W 24 x 117 24.3W 24 x 104 24.1W 24 x 94 24.1W 24 x 84 24.1W 24 x 76W 24 x 68 23.7W 24 x 62 23.7W 24 x 55 23.6130.7051.22047.7162517044341468.412.90.6501.09043.0146458039137160.512.90.6050.96038.5131402034032953.012.80.550.85034.4117354029729146.512.750.5000.75030.6104310025925840,79.070.5150.87527.794270010922224.09.020.4700.77024.784237094.419620.923.90.4400.68022.476210082.517618.48.970.4150.58520.168183070.415415.77.040.4300.59018.262155034.51319.87.010.3950.50516.255135029.11148.3W 1 x 147 22.1 12.51W 21 x 132 21.8 12.44W 21 x 122 21.7 12.39W 21 x 111 21.5 12.34W 21 x 101 21.4 12.29W 21 x 93 21.6W 21 x 83 21.4W 21 x 73 21.2W 21 x 68 21.1W 21 x 62W 21 x 57 21.1W 21 x 50 20.8W 21 x 44 20.70.7201.15043.2147363037632960.10.6501.03538.8132322033329553.50.6000.96035.9122296030527349.20.5500.87532.7111267027424944.50.5000.80029.8101242024822740.38.420.5800.93027.393207092.919222.18,360.5150.83524.383183081.417119.58.30.4550.74021.573160070.615117.08.270.4300.68520.068148064.714015.7218.240.4000.61518.362133057.512713.96.560.4050.65016.757117030.61119.46.530,3800.53514.75098424.994.57.66.50.3500.45013.04484320.781.66.4W 18 x 1191911.270.6551.06035.1119219025323144.9W 18 x 106 18.7W 18 x 97 18.6 11.15W 18 x 86 18.4 11.09W 18 x 76 18.2 11.04W 18 x 71 18.5 7.64W 18 x 65 18.4 7.59W 18 x 60 18.2W 18 x 5511.20.5900.94031.1106191022020439.40.5350.87028.597175020118836.10.4800.77025.386153017516631.60.4250.68022.376133015214627.60.4950.81020.871117060.312715.80.4500.75019.165107054.811714.47.560.4150.69517.66098450.110813.318.17.530,3900.63016.25589044.998.311.9W 18 x 5018750.3550.57014.75080040.188.910.7

Outer diameter = d1 = 100mm Thickness = t = 20mm Inner diameter = d2 = d1 - t = 100 - 20 = 80mm

Answered: What is the section modulus of a tube…

What is the section modulus of a tube with a diameter of 100mm measured from the outside and has a thickness of 20mm. Use whole number in mm^4. *

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

An aluminum plate is subjected to uniform stress along its boundaries, as shown in the figure. Determine the change of length of diagonal BD. 120mm 120 MPa 160mm , 100мра C 240 MPa E=80GPa ✓=0.3 G=30GPa Answer = -0.5888mm
A 20-mm-wide block is firmly bonded to rigid plates at its top and bottom. When the force P is applied the block deforms into the shape shown by the dashed line. (Figure 1) Part A Determine the magnitude of P. The block's material has a modulus of rigidity of G= 24 GPa .Assume that the material does not yield and use sma angle analysis. Express your answer to three significant figures and include the appropriate units. Figure µA ? Value kN P = 150 mm- You have already submitted this answer. Enter a new answer. No credit lost. Try again. 0.5 mm -- Submit Previous Answers Request Answer 150 mm Provide Feedback Next >
Two uniform spheres are positioned as shown. Determine the gravitational force F which the titanium sphere exerts on the copper sphere. The value of R is 35 mm. Copper y | 2.9 R j) (108) N R 5.8 R Titanium Answer: F = (i 28° i+ T IN
The shaft, which has a length of 800mm and a diameter of 25mm, broke, creating a gap of 10mm as indicated in the figure. To reconnect the shaft, force can be applied only to one of the broken point (B or C). The material has a modulus of elasticity of 690 MPa. Determine the minimum force required and provide your answer in kN with two decimal points of accuracy. A Answer: 300 mm 10 mm 500 mm B с
QUESTION 2 The bar shown has a cross-sectional area of A Young's modulus of E and a length of L. It is carrying a force of F. Calculate the normal stress (a) in the bar. F F O k Your unique values to use are (everybody will get different values for every question): 45 KN 4256 mm A 426 mm² 220 GPa Your mark will be based entirely on the answer you select from below. 0 = 233 MPa o=151 MPa 0=171 MPa = 190 MPa a=202 MPa a = 92 MPa 0 52 MPa 0122 MPa 0=76 MPa 0= 145 MPa 0-62 MPa o=140 MPa d=212 MPa 0106 MPa 0-100 MPa
200KN A steel rod is rigidly attached between an aluminum and bronze rod. The diameters of each material are shown in the figure. A fixed support is rigidly attached to the right end of the bronze rod. Determine the stress each section in kPa. Aluminum Steel D=28mm D=20mm 20KN Bronze D=25mm 150KN
A compound shaft consisting of aluminum segment and a steel segment is acted upon by two torques as shown. Determine the maximum permissible value of T subject to the following conditions: Stress at steel = 100 Mpa, Stress on Aluminum = 70 Mpa, and the angle of rotation of the free end is limited to 12°. Use G of steel = 83Gpa, G of aluminum = 28Gpa. 75 mm Somm 2T Steel A LUMINUM 2m 1,5m
A l-m long steel bar (E = 200 GPa) of 10 x10 mm dimension fixed at one end and free at the other end is heated to 90°C from initially 30°C. What is the normal stress, in MPa, induced in the system đue to change in temperature? Use a = 12 x 10-6 per °C. Encode you answer in whole number. Round your answer to 0 decimal places. Add your answer A 5 cm diameter steel suspension cable fixed at the upper end with length 20 m is subjected to load P = 5 kN at its lowest end. If the cable weighs 7850 kg per cum and modulus of elasticity is 200 GPa, what is the deformation of the cable due to the applied P alone in mm? Round your answer to 2 decimal places. Add your answer
A circular bar of magnesium alloy is 390 mm long. The stress-strain diagram for the material is shown in the figure. 70 63 56 49 O (MPa) 42 35 28 21 14 7 0.002 0.004 0.006 0.008 0.01 The bar is loaded in tension to an elongation of 2.34 mm, and then the load is removed. Hint: Use the concepts illustrated in the figures below. (Assume the curve in the figure above is linear between (0, 0) and (0.001, 28), and curves with a gradually decreasing slope otherwise.) F В E F Loading CD Loading Residual Elastic strain recovery (a) What is the permanent set of the bar (in mm)? 2.184 X mm (b) If the bar is reloaded, what is the proportional limit (in MPa)? 55 X MPa
Hw.s An open cylinder can has an inside radius of 2 cm and an inside height of 5 cm use the total derivative to estimate the Volume of cylinder metal if it is 0.ol cm thickness.
GIVEN: Bar has a cross-sectional area of 4 in? and is placed between two rigid immoveable supports when it is 30.00 inches long at a temperature of -20°F. REQ’D: A) The stress in the bar at 90°F if it were made of steel. Esteel = 10 x 10° psi asteel = 13 x 106/°F B) The final length of the aluminum bar
A square plastic bar (length Lp, side dimension sp = 193 mm) is inserted inside a hollow, square, cast iron tube (length Lc = 400 mm, side sc = 200 mm, and thickness tc = 3mm). (a) What is the required initial length Lp of the plastic bar so that, when it is compressed by some force P, the final length of bar and tube are equal to legnth Lc, and, at the same time, the gap between plastic bar and cast iron tube is closed? (b) Compare initial and final volumes for the plastic bar. Assume that Ec = 170 GPa, Ep = 2.1 GPa, vc = 0.3, and vp = 0.4.