What is the yield strength, ultimate tensile strength, and shear strength of a Carbon Graphite Rod grade JC3, if its diameter is 3.75 inches
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What is the yield strength, ultimate tensile strength, and shear strength of a Carbon Graphite Rod grade JC3, if its diameter is 3.75 inches?
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Which equations did you use to calculate these values? Or which machinery book did this info come from?
- HW:No.2 (The deadline for submitting your homework on Sandety (404.2014). Three steel bars with a diameter of 25 mm and carbon contents of 0.2, 0.5, and 0.8%, respectively. The specimens were subjected to tension until rupture. The load versus deformation results were as shown in Table below If the gauge length is 50 mm, determine the following: a. The tensile stresses and strains for each specimen at each load increase. b. Plot stresses versus strains for all specimens on one graph. c. The modulus of elasticity for each specimen. d. ultimate strength for each specimen. e. The strain at rupture for each specimen. f. the percentage of the total elongation. 3. Specimen No. Carbon Content (%) 1. 2 0.2 0.5 0.8 Deformation (mm) Load (kN) 0.00 0. 0.07 133 133 133 0.10 137 191 191 0.15 • 142 196 285 0.50 147 201 324 1.00 140 199 383 2.50 155 236 447 5.00 196 295 491 (Rupture) 7.50 226 336 10.00 241 341 12.50 218 304 (Rupture) 13.75 196 (Rupture)412/2021. HW:No.2 (The deadline for submitting your homework on Snday 042814). Three steel bars with a diameter of 25 mm and carbon contents of 0.2, 0.5, and 0.8%, respectively. The specimens were subjected to tension until rupture. The load versus deformation results were as shown in Table below If the gauge length is 50 mm, determine the following: a. The tensile stresses and strains for each specimen at each load increase. b. Plot stresses versus strains for all specimens on one graph. c. The modulus of elasticity for each specimen. d. ultimate strength for each specimen. e. The strain at rupture for each specimen. f. the percentage of the total elongation. 3 Specimen No. Carbon Content (%) 1 2 0.2 0.5 0.8 Deformation (mm) Load (kN) 0.00 0. 0. 0. 0.07 133 133 133 0.10 137 191 191 0.15 • 142 196 285 0.50 147 201 324 1.00 140 199 383 2.50 155 236 447 5.00 196 295 491 (Rupture) 7.50 226 336 10.00 241 341 12.50 218 304 (Rupture) 13.75 196 (Rupture) Stress Strain Curve and Explanation…100 types of steel failures
- A 32-mm rebar with a gauge length of 200 mm was subjected to tension to fracture according to ASTM E-8 method. The load and deformation data were as shown in Table P3.33. Using a spreadsheet program obtain the following: a. A plot of the stress-strain relationship. Label the axes and show units. b. A plot of the linear portion of the stress-strain relationship. Determine modulus of elasticity using the best-fit approach. c. Proportional limit. d. Yield stress. e. Ultimate strength. f. If the rebar is loaded to 390 kN only and then unloaded, what is the permanent change in length? TABLE P3.3 3 Load (kN) Displacement (mm) Load (kN) Displacement (mm) 472.9 8.4 62.2 0.1 487.1 9.7 188.9 0.2 496.4 11.1 329.8 0.4 505.7 12.4 383.4 1.7 512.8 13.7 426.0 4.0 522.6 15.3 447.3 5.9 532.4 18.5 462.5 7.2 525.9 22.4Three steel bars have a diameter of 25 mm and carbon contents of 0.2, 0.5, and 0.8%, respectively. The specimens were subjected to tension until rupture. The load versus deformation results were as shown in Table P3.19. If the gauge length is 50 mm, determine the following: a. The tensile stresses and strains for each specimen at each load increment. b. Plot stresses versus strains for all specimens on one graph. TABLE P3.19 Specimen No. Carbon Content (%) 1 3 0.2 0.5 0.8 Deformation (mm) Load (kN) 0.00 0.07 133 133 133 0.10 137 191 191 0.15 142 196 285 0.50 147 201 324 1.00 140 199 383 2.50 155 236 447 5.00 196 295 491 (Rupture) 7.50 226 336 10.00 241 341 12.50 218 304 (Rupture) 13.75 196 (Rupture) c. The proportional limit for each specimen. d. The 0.2% offset yield strength for each specimen. e. The modulus of elasticity for each specimen. f. The strain at rupture for each specimen. g. Comment on the effect of increasing the carbon content on the following: Yield strength ii.…Three steel bars have a diameter of 25 mm and carbon contents of 0.2, 0.5, and 0.8%, respectively. The specimens were subjected to tension until rup- ture. The load versus deformation results were as shown in Table P3.19. If the gauge length is 50 mm, determine the following: a. The tensile stresses and strains for each specimen at each load increment. b. Plot stresses versus strains for all specimens on one graph. TABLE P3.19 Specimen No. Carbon Content (%) Deformation (mm) 1 2 3 0.2 0.5 0.8 Load (kN) 0.00 0.07 133 133 133 0.10 137 191 191 0.15 142 196 285 0.50 147 201 324 1.00 140 199 383 2,50 155 236 447 5.00 196 295 491 (Rupture) 7.50 226 336 10.00 241 341 12.50 218 304 (Rupture) 13.75 196 (Rupture) c. The proportional limit for each specimen. d. The 0.2% offset yield strength for each specimen. e. The modulus of elasticity for each specimen. f. The strain at rupture for each specimen. g. Comment on the effect of increasing the carbon content on the following: i. Yield strength ii.…
- What is the relationship between penetration hardness and the ultimate tensile strength for steel?A rectangular steel bar 0.5 inch thickness by 1.5 inches width and 220 ft long is subjectedto a 6000 lbs tensile load acting along its width. Find the deformation along its length andthickness if poison’s ratio is 0.27.hree steel bars with a diameter of 25 mm and carbon contents of 0.2, 0.5, and 0.8%, respectively. The specimens were subjected to tension until rupture. The load versus deformation results were as shown in Table P3.19. If the gauge length is 50 mm, determine the following: The tensile stresses and strains for each specimen at each load increment. Plot stresses versus strains for all specimens on one graph. The proportional limit for each specimen. The 0.2% offset yield strength for each specimen. The modulus of elasticity for each specimen. The strain at rupture for each specimen. Comment on the effect of increasing the carbon content on the following: Yield strength ii. Modulus of elasticity iii. Ductility
- A grade 36 round steel bar with a diameter of 0.5 inches and a gauge length of 2 inches wassubjected to tension to rupture following ASTM E-8 test procedure. The load and deformation data wereas shown in the following table: Using a spreadsheet program obtain the following:a. A plot of the stress-strain relationship. Label the axes and show units.b. A plot of the linear portion of the stress-strain relationship. Determine modulus of elasticity usingthe best fit approach.c. Proportional limit.d. Yield stress.e. Ultimate strength.f. When the applied load was 4.07 kips, the diameter was measured as 0.499905 inches. DeterminePoisson’s ratio.g. After the rod was broken, the two parts were put back together and the diameter of at the neckwas measured as 0.416012 inches. What is the true stress value at fracture? Is the true stress atfracture larger or smaller than the engineering stress at fracture? Why?h. Do you expect the true strain at fracture to be larger or smaller than the…A bar made of high strength low-carbon steel of GRade 50 (yield strength gauge 50 ksi) , is 0.5 inchthick and 1.2 inch wide. The ultimate tensile strength of the steel is 70 ksi. Determine the load at whichthe bar starts to yield and also determine the load when the bar is likely to fracture. Taking the originalgauge length to as 5 inches and Young’s modulus of steel as 30 x 10^6 psi, estimate the new gauge lengthwhen the specimen is stressed at 2/3 of the yield stress.List four failure modes in structural steel design