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- The stresses acting on a stress element on the arm of a power excavator (see figure) are ax= 52 MPa and txy= 33 MPa (sec figure). What is the allowable range of values for the stress if the maximum shear stress is limited to = 37 MPa?-7 Repeat Problem 2.3-5, but n include the weight of the bar. See Table I-I in Appendix I for the weight density of steel.- A specimen used in a coupon test has norm al stress ??. = 15 MPa (see figure). Using Mohr’s circle, find the state of stress on the element oriented at angle ? = 20° and show the full stress state on a sketch of a properly oriented element.
- 4. The general stress element is loaded such that ơx = 30 MPa, oy = -20 MPa, Txy = 5 MPa. Using Mohr's circle, find out the maximum normal stress and shear stress acting on this element. 5. The general stress element is loaded such that ơ, = 50 MPa. Using Mohr's circle, find out the maximum normal stress and shear stress acting on this element. (Simple tension)At point O of a part subjected to plane stress made of steel material (E = 210 GPa and v= 0.3) the tensile components are given below. 240 50 0= , o, Tyz 50 - 30 %3D MPa 0 0 a) The principal stress components (01, 02 and o3) and their angles with respect to the x-y-z axes of the planes where they are formed calculate. b) Calculate the maximum shear stress (tmax). c) Drawthe 2-D and 3-D Mohr circles for the stress components. d) If the yield strength of the steel material is 250 MPa, according to the Tresca ww damage criterion, it will not flow at the O point of the part. Indicate whether it is safe or not.The rectangular bar made of the two materials in the figure undergoes the moment of M kN.m. Find the maximum stress and plot the stress distribution on your answer sheet.
- 4. The general stress element is loaded such that Tw = 25 MPa. Using Mohr's circle, find out the maximum normal stress and shear stress acting on this element. (Pure torsion please elaborate what is pure torsionWhat are the equation used for part a)? for the axial stress, why do we not use Axial Stress = Pr/(2t)? Also, the math for the pricipal stresses is incorrect.find the principal stress , maximum in plane shear stress , average normal stress specdify the orientation of the element in each case , use mohrs circle to solve the question .
- At point O of a part subjected to plane stress made of steel material (E = 210 GPa and %3D ww v= 0.3) The tensile components are given below. 240 %3D - 30 MPa *yz yz a) The principal stress components (01, 02 and o3) and their angles with respect to the x-y-z axes of the planes where they are formed calculate b) Calculate the maximum shear stress (tmax) and the angles of the plane in which it is formed with respect to the x-y-z axes. c) Drawthe 2-D and 3-D Mohr circles for the stress components. d) At point O in a section plane passing through point O and having an angle of 30° counterclockwise with the +x-axis Calculate the resulting stress components. e) Calculate the strain components (Exx, EW, Ezz, YXV, YXz and Yyz) and draw the 2-D and 3-D Mohr circles for the strain components.4-Find the stresses in each direction, also find the change in volume of the block of dimension 110 mm x 50 mm x 31 mm, subjected to 3 mutually perpendicular loads. The load along length, breadth and depth directions are 22 kN (tensile), 30 kN (compressive), 22 kN (compressive) respectively. Take E as 100 GPa, Poisson’s ratio as 0.3 The stress along length direction (Unit in MN/m2)= _____________ The compressive stress along width direction (Unit in MN/m2)= _____________ The compressive stress along depth direction (Unit in MN/m2)= _____________ The change in volume of the block is (unit in mm3) = ______________A member is subjected to a major stress of 110 MPa (tensile), minor stress of 40 MPa (tensile) along with a counter clockwise shear stress of 30 MPa. Calculate the Normal stress, tangential stress, Resultant stress and its inclination on plane make 20 to major stress. Validate your analytical results by drawing Mohr’s circle. i) Normal Stress (unit is MPa) = (ii) Tangential Stress (unit is MPa) = ) Resultant Stress (unit is MPa) Resultant inclination (unit in degree) =