When the following gas reaction reaches equilibrium, at a certain temperature, the moles fractions four reactive species satisfy the following relation (we will use "y" for mole fractions since all of thes reagents and products are gases): CO+H20 CO2+H2 K= [yCO2][yH2] [yCo][YH20] Where K= 1. Assume that the feed introduced to the reactor is 2 mol of CO and 4 mol of H20 only. Al: assume that the reaction reaches equilibrium. a) Calculate the equilibrium composition, for this you need to calculate the mole fraction for all reactants and products. Answer: yCo2 = 2/9 yH2 yCo = 1/9 YH2O = 4/9| = 2/9

World of Chemistry, 3rd edition
3rd Edition
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Chapter17: Equilibrium
Section: Chapter Questions
Problem 38A
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When the following gas reaction reaches equilibrium, at a certain temperature, the moles fractions of the
four reactive species satisfy the following relation (we will use "y" for mole fractions since all of these
reagents and products are gases):
CO+H20 >
CO2+H2
[yCO2][yH2]
K=
[yC0][YH20]
Where K= 1. Assume that the feed introduced to the reactor is 2 mol of CO and 4 mol of H20 only. Also
assume that the reaction reaches equilibrium.
need to calculate the mole fraction for all
a) Calculate the equilibrium composition, for this
reactants and products.
Answer: yCo2 = 2/9
= 2/9
yH2
УСо - 1/9
YH2O = 4/9|
Transcribed Image Text:When the following gas reaction reaches equilibrium, at a certain temperature, the moles fractions of the four reactive species satisfy the following relation (we will use "y" for mole fractions since all of these reagents and products are gases): CO+H20 > CO2+H2 [yCO2][yH2] K= [yC0][YH20] Where K= 1. Assume that the feed introduced to the reactor is 2 mol of CO and 4 mol of H20 only. Also assume that the reaction reaches equilibrium. need to calculate the mole fraction for all a) Calculate the equilibrium composition, for this reactants and products. Answer: yCo2 = 2/9 = 2/9 yH2 УСо - 1/9 YH2O = 4/9|
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