When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.60-cm-tall object is 59.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of An image of an image. Part A Find the location and height of the image (call it I₁) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated with a comma. [ΕΑΣΦΗ s₁.lv 120,2.40 Submit 3 Previous Answers Request Answer ? cm

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter26: Image Formation By Mirrors And Lenses
Section: Chapter Questions
Problem 40P
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When two lenses are used in combination, the first one forms an
image that then serves as the object for the second lens. The
magnification of the combination is the ratio of the height of the final
image to the height of the object. A 1.60-cm-tall object is 59.0 cm to
the left of a converging lens of focal length 40.0 cm. A second
converging lens, this one having a focal length of 60.0 cm, is located
300 cm to the right of the first lens along the same optic axis.
For related problem-solving tips and strategies, you may want to view
a Video Tutor Solution of An image of an image.
Part A
Find the location and height of the image (call it I₁ ) formed by the lens with a focal length of 40.0 cm.
Enter your answers in centimeters separated with a comma.
ΨΠ ΑΣΦ
s, y 120,2.40
=
Submit
Previous Answers Request Answer
?
cm
Transcribed Image Text:When two lenses are used in combination, the first one forms an image that then serves as the object for the second lens. The magnification of the combination is the ratio of the height of the final image to the height of the object. A 1.60-cm-tall object is 59.0 cm to the left of a converging lens of focal length 40.0 cm. A second converging lens, this one having a focal length of 60.0 cm, is located 300 cm to the right of the first lens along the same optic axis. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of An image of an image. Part A Find the location and height of the image (call it I₁ ) formed by the lens with a focal length of 40.0 cm. Enter your answers in centimeters separated with a comma. ΨΠ ΑΣΦ s, y 120,2.40 = Submit Previous Answers Request Answer ? cm
Part B
I₁ is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of
lenses.
Enter your answers in centimeters separated with a comma.
ΠΑΣΦ
s2, y2 = 49.29,. 116
Submit
Previous Answers Request Answer
?
.
cm
Transcribed Image Text:Part B I₁ is now the object for the second lens. Find the location and height of the image produced by the second lens. This is the final image produced by the combination of lenses. Enter your answers in centimeters separated with a comma. ΠΑΣΦ s2, y2 = 49.29,. 116 Submit Previous Answers Request Answer ? . cm
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