Which hydrogen (proton) should be removed to form the MOST STABLE alkene? Please look in photo for labeled protons! wCH ROGIN WILL BE ABSTRACTED + H,0 CNTRUE REPLAY
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- 027 In Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 4 See Periodic Table O See Hint :0: :Br: Add the missing curved arrow notation. S CI Br Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Kea > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e., Keq« 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg 1) because bromide is a better leaving group than acetate. +Q, - write a Mechanism that explains hint he stereochemisty (sed pmacal rearangemendy a) CotH6 fonn Hcl b) HeoH O wr,te he Mechanism fer OH CHBrg NAOH (Carbene)The given reaction scheme is an example of which type of reaction? O || R₁-C-OH + R₂-OH Oxidation Fischer esterification Nucleophilic substitution Reduction Rearrangement reaction Acid O || R₁-C-O-R₂ Meeting in "General"
- Explain why furan is primary substituted at the 2 positive when it undergoes reaction. E* E an EASIn Part 1 add the curved arrows to the nucleophilic acyl substitution reaction mechanism. In Part 2, answer the multiple-choice question about the reaction in Part 1. Part 1 See Periodic Table O See Hint :ö: :Br: Add the missing curved arrow notation. 20 F CI Br I Part 2 Which statement is most correct regarding the equilibrium for the above reaction? Choose one: O The equilibrium favors the right (i.e., Kea > 1) because acetate is a better leaving group than bromide. O The equilibrium favors the right (i.e., Keg > 1) because bromide is a better leaving group than acetate. O The equilibrium favors the left (i.e. Keg « 1) because acetate is a better leaving group than bromide. O The equilibrium favors the left (i.e., Keg« 1) because bromide is a better leaving group than acetate.ew fopics] Draw the major organic product of the reaction shown below. H2SO4 HO, • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • In cases where there is more than one answer, just draw one. C opy aste [F ChemDoodle
- Draw the organic product formed in the following reaction. H-N Job OEt OEt [1] NaOEt [2] CI [3] H₂O+, A NHAC HO "CH₂ edit structure ...Question 5 1). Draw all resonance structures for the carbocation intermediate formed by para attack; circle the resonance structure that is particularly unstable. N- N Cl₂ AICI 3 H 2). Draw all resonance structures for the carbocation intermediate formed by ortho attack; circle the extra resonance structure that is particularly stable. H a Aer ANSAS C HNO3 H₂SO4Identify the major product of the reaction of an alkene shown below. ||| 1. Hg(OAc)2, H2O 2. NaBH4, NaOH ....... ОН || IV ОН о, ОН
- Rank the compounds in order of reactivity toward nitration with HNO3: benzene 2-methylfuran thiophene Most reactive Least reactive Answer Bank 3-methylthiopheneCurved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic steps. Be sure to account for all bond-breaking and bond-making steps. H H y H H ✪ I CH3OH heat CH3OH heat HH H : Br: O CH3OH heat Drawing ArrowsDraw the final product of this series of reactions. |||** OH 1. SOCI₂ 2. NaCN • Use the wedge/hash bond tools to indicate stereochemistry where it exists. • If more than one product is possible, only draw the major product. • If the reaction produces a racemic mixture, draw both stereoisomers.