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- Q1__;. A phrase is a palindrome if, after converting all uppercase letters into lowercase letters and removing all non-alphanumeric characters, it reads the same forward and backward. Alphanumeric characters include letters and numbers. Given a string s, return true if it is a palindrome, or false otherwise. Example 1: Input: s = "A man, a plan, a canal: Panama" Output: true Explanation: "amanaplanacanalpanama" is a palindrome. Example 2: Input: s = "race a car" Output: false Explanation: "raceacar" is not a palindrome..Which of these methods of class String is used to check whether a substring exists at the beginning of the particular string? a) StartsWith() b) EndsWith() c) Starts() d) ends()The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive. For example: countSubstring(“catwoman loves cats”, “cat”) would return 2 countSubstring(“aaa nice”, “aa”) would return 1 because “aa” only appears once without overlapping itself. public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1; if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); } public class Main { public static void main(String[] args) { System.out.println(Recursion.countSubstring("catwoman loves cats","cat"));…
- Review the code snippet below: sentence = input ("Enter some text: ") firstCh = sentence [0] Which of the following statements correctly determines if the first letter of the string contained in sentence is an uppercase letter? Select one: if not (firstCh.isupper ()) : if firstCh.isspace ( : if firstCh.isupper ( : if not (firstCh.isspace ()): CflnotingReview the code snippet below: sentence = input ("Enter some text: ") firstCh = sentence [0] Which of the following statements correctly determines if the first letter of the string contained in sentence is an uppercase letter? Select one: if not (firstCh.isupper ()) : it firetCh.isapace () if firstCh.isupper () if not (firstCh.isspace ()) :a. If str="Long String", what will be the value of the following variables: a. String str1=str.substring(3,str.indexOf("i")); b. String str2 = str1.toUpperCase().substring(5)+str.substring(0,3); c. boolean test=str1.toUpperCase().indexOf("r") == str1.indexOf("r");
- Review the code snippet below: sentence = input ("Enter some text: ") firstch = sentence [0] Which of the following statements correctly determines if the first letter of the string contained in sentence is an uppercase letter? Select one: O if not (firstch.isupper()) : if firstch.isspace(): O if firstch.isupper(): O if not (firstch.isspace()) :Write a code that determines if a string is a palindrome (can be read forward and backward with the same meaning); e.g. "civic", “elle", “madam" 66 22what is String.Empty constant ?
- In Programming When you work with text, sometimes you need to determine if a given string starts with or ends with certain characters. You can use two string methods to solve this problem: .startswith() and .endswith()?You are given a string ternary_expr which represents a random nested ternary expression, you need to evaluate this expression, and report the result. Assumption can be as follows: ● ternary_expr only contains digits, ‘?’, ‘:’, ’T’, ‘F’ where ’T’ is true and ‘F’ is false. ● ternary_expr contains only one-digit numbers (i.e. in the range [0, 9]) The ternary expressions group right-to-left, and the result of the expression will always evaluate to either a digit, 'T' or 'F'. Requirements 1. Way of modeling the problem with the cost implications without using Stacks.a string from user an —Final string. In Cit