which q point in the load line will the maximum output swing be obtained? please write a simple equation how to obtain this q point( the iD and VSD)
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In which q point in the load line will the maximum output swing be obtained? please write a simple equation how to obtain this q point( the iD and VSD)
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- Q-3: A- By using graphical approach, find Ipo and Vcso for the figure shown, where VDp = 9V, Rp = 3KN, RF 11MN, Ip(on) = 7mA, Vcs(on) =4.5V and V=3.5V. %3D VDD RD C2 oVo Rf C1 ViOWhat can you say about AM DSB-FC, AM DSB-SC, and AM SSB? What do they have in common and their difference?When comparing values for shape factor: a. A value of 0.707 is ideal b. There is no ideal value c. A value of 1.414 dB is ideal d. A value of 1.0 is deal
- Explain dual slope ADC and successive approximation ADC with neat block diagram and compare the two approachesMultiple choice question. The parameters of a PV module are Voc=36V, Imp=15.5A, Isc=31A, Vmp=30.8V. What is the output voltage and current if a configuration consists of the six PV modules connected in parallel? (1) A. 216 V and 93 A B. 184.8 V and 15.5 A C. 30.8 V and 93 A D. 216 V and 31 AIn the circuit given in the figure | VBE | Since = 0.7V, R1 = 2.66Kohm, R2 = 11.73Kohm, RC = 0.79Kohm, RE = 2.36Kohm, VCC = 14.00V, Beta = 115.00, calculate the IC current by full analysis. When making your transactions, 2 steps will be taken after the point. Select the closest option according to +/- 10% margin of error. There is only one correct answer to the question.
- The current gain for each stages are and respectively. Ajs is equal to (two decimal places, do not use comma (,) for high values). The phase relationship between Vi and Vo is Rs-6202 |Z=15KQ Zo= 2.2 k2 AVNL = -250 Zi=5 KO Zi=80 Zo=150 Zo= 6.8 K2 RL-5.6K2 Vs AVNL = 0.95 AVNL = 300 CE CC CBIn the circuit given in the figure | VBE | = 0.7V, R1 = 11.06Kohm, R2 = 48.24Kohm, RC = 1.03Kohm, RE = 3.09Kohm, VCC = -13.00V, Beta = 150.00, calculate the IC current by full analysis.2. The circuit given below is using a transformer of 230V/30V. The load resistance is 10KS. Find Vin (rms and peak values), Vdiode and VLOAD (Peak and dc values). Draw the input and output voltage waveforms. (Si diode) Vin: Vin rms= Vin peak = VDIODE Vdiode = 4 Vin VLOAD: VLOAD Peak =. Load VLOAD VLOAD DC= 2031 Supply wwwwww
- For the circuit shown in figure. Vcc For the cireuit shown in Figuye If Ve=lor, B=200, 2.5k2 RI - 10v IkszSIGNAL Mention the function or work of each component in the circuit? + Vcc Rc Rc Cc HH www R₁ Cin HH R₂ www. RE Cc HH CE www R₁ 30 www wwww RE CE OUTPUTIn the circuit given in the figure, Rk = 8.70Kohm, R1= 5277.50Kohm, R2=5722.50Kohm, R3 =4.31Kohm, R4=1.44Kohm, R5=24.60ohm, Ry=81.59Kohm, VCC-11.00V,VTN=2.79V, Kn= Since 4.56(mA/V*2), C1= 9.03uF, C2= 6.28uF, C3= 5.81uF, the undercut frequency of the circuit is Hz calculate it in terms of. When performing your operations, 2 steps will be taken after the point, according to the ±10% margin of error you found write the result In Hz. When typing the answer, the space in front of the value behind the font (Hz, KHz) V.b. values should not be written. Only numerical values should be entered. Dot as decimal bracket (.) should be used. An example illustration is given below. Let the value you found be 1.15K. You should write 1150.00 In the box. Let the value you found be 432.6. You should write 432.63 In the box. If the correct answer is X, the values entered in the December X + (X*10/100) (including limits) will be accepted. If X=50, the Dec between [45,55] will be accepted. 2 Rk www VS C1 +18…