((I will consider IAB as the reference)) Hello, please, I need the complete solution along with a clear and understandable pasor diagram. Thank you. Example:A three-phase, 339.4 V, ABC system shown below has a A connected load, with:ZAB= 10/0° 2ZBC= 10/30 22Zc=15-30° 2Obtain phase and line currents and draw the phasor diagram.Solution:LAB=1VCABVABVac339.4/12010/0LABSimilarly, Lac = 33.94/-30 A and I=22.63/270° A. Then,Also, Ig=65.56-45 A and Ic=29.93/-169.1 A.100 010/30== 33.94/120 A15/-3P 11IscL₁=1+1=33.94/120-22.63/270-54.72/108.1 AkaTABICA

Answered: Image /qna-images/answer/c41ff570-dfea-4937-8021-0338c2bdb42c.jpg

Answered: will consider IAB as the reference))…

will consider IAB as the reference)) Hello, please, I need the complete solution along with a clear and understandable pasor diagram. Thank you.

Power System Analysis and Design (MindTap Course List)

6th Edition

ISBN:9781305632134

Author:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Publisher:J. Duncan Glover, Thomas Overbye, Mulukutla S. Sarma

Chapter2: Fundamentals

Section: Chapter Questions

Problem 2.14MCQ: The instantaneous power absorbed by the load in a single-phase ac circuit, for a general R LC load...

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Dielectric Breakdown

A dielectric is a material with low electrical conductivity and so is classified as an insulator. Dielectric materials are used to block the flow of electricity through them, allowing them to behave as an insulators. They can also be used to store electric charge or improve capacitance.Dielectrics have no free electrons for conduction because electrons are tightly bound to the nucleus. Because dielectrics contain a small number of electrons for electrical conductivity, they have a dipole. The two primary roles of dielectrics in electrical devices are insulation and electrical energy storage. An electric field polarizes the dielectric, and the polarization of the molecules allows dielectric materials to store charge.

Question

((I will consider IAB as the reference)) Hello, please, I need the complete solution along with a clear and understandable pasor diagram. Thank you.

Example:
A three-phase, 339.4 V, ABC system shown below has a A connected load, with:
ZAB= 10/0° 2
ZBC= 10/30 22
Zc=15-30° 2
Obtain phase and line currents and draw the phasor diagram.
Solution:
LAB=1
VCA
B
VAB
Vac
339.4/120
10/0
LAB
Similarly, Lac = 33.94/-30 A and I=22.63/270° A. Then,
Also, Ig=65.56-45 A and Ic=29.93/-169.1 A.
100 0
10/30
== 33.94/120 A
15/-3P 11
Isc
L₁=1+1=33.94/120-22.63/270-54.72/108.1 A
ka
TAB
ICA

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