//write a recursion function that will find the largest interger in the string. Can you give me some feedback on this function public int findMax(String s,intmax) { if (s.length()== 0) return 1; for (int = 0 ; i > s.length() ;i++) if (s.charAt (i) > s.charAt(i) )) returnmax; returnmax;
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//write a recursion function that will find the largest interger in the string.
Can you give me some feedback on this function
public int findMax(String s,intmax)
{
if (s.length()== 0)
return 1;
for (int = 0 ; i > s.length() ;i++)
if (s.charAt (i) > s.charAt(i) ))
returnmax;
returnmax;
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- For function addOdd(n) write the missing recursive call. This function should return the sum of all postive odd numbers less than or equal to n. Examples: addOdd(1) -> 1addOdd(2) -> 1addOdd(3) -> 4addOdd(7) -> 16 public int addOdd(int n) { if (n <= 0) { return 0; } if (n % 2 != 0) { // Odd value return <<Missing a Recursive call>> } else { // Even value return addOdd(n - 1); }}Write a recursive function called that takes a string of single names separated by spaces and prints out all possible combinations (permutations), each combination on a new line. When the input is: Alice Bob Charlie then the output is: Alice Bob Charlie Alice Charlie Bob Bob Alice Charlie Bob Charlie Alice Charlie Alice Bob Charlie Bob Alice Here is my original code that needs to be fixed: def all_permutations(permList, nameList): # TODO: Implement method to create and output all permutations of the list of names. if nameList == len(permList) - 1: return nameList else: for x in range(permList, len(nameList)): permList[nameList], permList[x] = permList[x], permList[name_List] return all_permutations(permList, nameList + 1) permList[nameList], permList[x] = permList[x], permList[name_List] if __name__ == "main": nameList = input().split(' ') permList = [] all_permutations(permList, nameList)Write a recursive function called that takes a string of single names separated by spaces and prints out all possible combinations (permutations), each combination on a new line. When the input is: Alice Bob Charlie then the output is: Alice Bob Charlie Alice Charlie Bob Bob Alice Charlie Bob Charlie Alice Charlie Alice Bob Charlie Bob Alice Here is the original code in Python: def all_permutations(permList, nameList): # TODO: Implement method to create and output all permutations of the list of names. pass if __name__ == "__main__": nameList = input().split(' ') permList = [] all_permutations(permList, nameList)
- Write a recursive function (no auxiliary functions, for/while loops, STL containers or functions, static/global variables) bool mirrorMirrorOnTheWall(string n); Given a string, recursively determine if the string is the same forwards and backwards. mirrorMirrorOnTheWall(""); mirrorMirrorOnTheWall("a"); mirrorMirrorOnTheWall("mirror"); // returns false mirrorMirrorOnTheWall("racecar"); // returns true // returns true // returns true Edit View Insert Format Tools Table 12pt v Paragraph v BIU ...Recursive Palindrome! Recall that a palindrome is a string that reads the same forward and backward. Write a recursive function is_palindrome (s:str) -> bool to check whether a string s is a palindrome. Here's a hint: think about how you can use is_palindrome(t), where t is a substring of s, to help you decide whether s is a palindrome. Your Answer: 1 # Put your answer here 2 SubmitFor function decToBinary, write the missing parts of the recursion case. This function should return a string that stores the binary equivalent for int variable num. Example: The binary equivalent of 13 may be found by repeatedly dividing 13 by 2. So, 13 in base 2 is represented by the string "1101". Examples: decToBinary(13) -> "1101" public String decToBinary (int num) { if (num < 2) return Integer.toString(num); else return <<Missing recursive call>> + <<Missing calculation>>;}
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- Write a recursive function 'void reverse(string &word)' that reverses the given input string. string name = "lexa"; reverse(name); cout << name << endl; //should display "axel". without using the following loops: -no for loops -no while loops -no do-while's -no while-do's -no for-while's -no while-for-do'sConsider the below recursive function: public static void func (int n) if (n == 0) return; else { func(n-2); System.out.println(n); } Draw activaiton frames with n=8 and determine the output produced by this method.Java, I am not displaying my results correct. It should add up the digits in the string. input string |result for the sumIt Recursion functions and a findMax function that finds the largest number in a string "1d2d3d" | 6 total "55" |10 total "xx" | 0 total "12x8" |12 Max number "012x88" |88 Max Number "012x88ttttt9xe33ppp100" |100 Max Number public class Finder { //Write two recursive functions, both of which will parse any length string that consists of digits and numbers. Both functions //should be…